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How to use it?
How do you in partial fractions?
:
(4x-1)/(x^2-4x+8)
(x^3+2)/(x^3-4x)
x^2/(1-x^4)
(C^2-5c)/(c^2-25)
Factor polynomial
:
y^2+x^2+4*a^2+1-4*a*x-4*a+2*x+2*a*y
y^2-5
y^2+4*y-60
y^2-4*y
Least common denominator
:
x/2+x/4+x/8
-x^2/(x-1)^2+2*x/(x-1)
(x-2*cos(x)/sin(x)+2*x*cos(x)^2/sin(x)^2)/sin(x)
x^2-91/10-3*x*2/(x-4)-4*x*(-1)/((x^2-x-12)*(x+3))
Factor squared
:
-y^4+11*y^2+1
y^4+10*y^2+6
-y^4+10*y^2-13
y^4-10*y^2-1
Integral of d{x}
:
1/(x^2+2)
Graphing y =
:
1/(x^2+2)
Derivative of
:
1/(x^2+2)
Identical expressions
one /(x^ two + two)
1 divide by (x squared plus 2)
one divide by (x to the power of two plus two)
1/(x2+2)
1/x2+2
1/(x²+2)
1/(x to the power of 2+2)
1/x^2+2
1 divide by (x^2+2)
Similar expressions
1/(x^2-2)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2+2)
How do you 1/(x^2+2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ------ 2 x + 2
$$\frac{1}{x^{2} + 2}$$
1/(x^2 + 2)
Fraction decomposition
[src]
1/(2 + x^2)
$$\frac{1}{x^{2} + 2}$$
1 ------ 2 2 + x
Numerical answer
[src]
1/(2.0 + x^2)
1/(2.0 + x^2)