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How to use it?
How do you in partial fractions?
:
(y*x^2+16)/((y-1)*(x-4))-(16*y+x^2)/(x*y-x-4*y+4)
(9-m^2)/(m^2+3*m)
tan(x+pi/8)/2-1/(2*tan(x+pi/8))
(3*y^2-12)/(2*y^2-15*y+18)
Factor polynomial
:
z^2+8*z+41
z^2-8*p*z-z+4*p+16*p^2
z^2+5*i/z
z^2-4*z+16*z^2/16
Least common denominator
:
y/x-(x*y-x^2)/(y-1)*(y-1)/x^2
y^2+2*y+1/y-2/y+1
((x/(y^2+x*y))+((x-y)/(x^2-x*y)))/((y^2)/(x^3-x*y))+(1/(x-y))
x/x+1/x/x^2
Factor squared
:
-y^4-7*y^2+9
-y^4+9*y^2-13
y^4+8*y^2-3
y^4-6*y^2-6
Integral of d{x}
:
1/(x^2+2)
Graphing y =
:
1/(x^2+2)
Derivative of
:
1/(x^2+2)
Identical expressions
one /(x^ two + two)
1 divide by (x squared plus 2)
one divide by (x to the power of two plus two)
1/(x2+2)
1/x2+2
1/(x²+2)
1/(x to the power of 2+2)
1/x^2+2
1 divide by (x^2+2)
Similar expressions
1/(x^2-2)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2+2)
How do you 1/(x^2+2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ------ 2 x + 2
$$\frac{1}{x^{2} + 2}$$
1/(x^2 + 2)
Fraction decomposition
[src]
1/(2 + x^2)
$$\frac{1}{x^{2} + 2}$$
1 ------ 2 2 + x
Numerical answer
[src]
1/(2.0 + x^2)
1/(2.0 + x^2)