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How to use it?
How do you in partial fractions?
:
1/(x^4+x^2)
ln((x+(sqrt(x^2+1)))/(2x))
(m-(14*m-49)/m)/(7/m-1)
k/(k+6)^2-k/(k^2-36)+1/(k-6)^2
Factor polynomial
:
y^3-6*y^2*x+12*y*x^2-8*x^3
y^3+49+7+y^2
y^3+4^3
y^3-3*y+3^3
Least common denominator
:
(((x-8)/(x+8))-((x+8)*(x-8)))/8*x/(x^2-64)
((x+8)/x^(2/3)-2*x^(1/3)+4)-((x-8)/x^(1/3)+4)
(x^8-3)*(2/(5*(x^8-3))-8*x^7*(1+2*x)/(5*(x^8-3)^2))/(1+2*x)
x+(6-x^2/1+x)/6+x/(x^2-1)
Factor squared
:
y^4-4*y^2-12
-y^4+4*y^2-11
-y^4+4*y^2+1
-y^4-3*y^2+9
Integral of d{x}
:
1/(x^2+2)
Graphing y =
:
1/(x^2+2)
Derivative of
:
1/(x^2+2)
Identical expressions
one /(x^ two + two)
1 divide by (x squared plus 2)
one divide by (x to the power of two plus two)
1/(x2+2)
1/x2+2
1/(x²+2)
1/(x to the power of 2+2)
1/x^2+2
1 divide by (x^2+2)
Similar expressions
1/(x^2-2)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2+2)
How do you 1/(x^2+2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ------ 2 x + 2
$$\frac{1}{x^{2} + 2}$$
1/(x^2 + 2)
Fraction decomposition
[src]
1/(2 + x^2)
$$\frac{1}{x^{2} + 2}$$
1 ------ 2 2 + x
Numerical answer
[src]
1/(2.0 + x^2)
1/(2.0 + x^2)