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How to use it?
How do you in partial fractions?
:
2*log(x/(x-4))-3
((y-4)/(3*y-3)+1/(y-1))/(y+1)/3+2/(y^2-1)
(x^2-x-56)/(x^2-x-64)
cbrt((b^(1/2))/(sqrt(27*b^3))*(1/(b^-2))^(1/8))
Factor polynomial
:
z^2+9*z+27+27/z
z^2+3*z+8
-y-y^2/2
y^x*y^3-y-1+y^x*y
Least common denominator
:
(x-y/5*x-x+y)/y-x/8+8/5*x
(x-x*x*x/6+x*x*x*x*x/120)^3
(x+x^3/3)*log(x)-(x^3+9*x)/9
x/(x^2+y^2)-y*(x^3-y^3)/(x^4-y^4)
Factor squared
:
-y^4-7*y^2+2
y^4-7*y^2+5
y^4+6*y^2+4
y^4+5*y^2-4
Integral of d{x}
:
1/(x^2+2)
Graphing y =
:
1/(x^2+2)
Derivative of
:
1/(x^2+2)
Identical expressions
one /(x^ two + two)
1 divide by (x squared plus 2)
one divide by (x to the power of two plus two)
1/(x2+2)
1/x2+2
1/(x²+2)
1/(x to the power of 2+2)
1/x^2+2
1 divide by (x^2+2)
Similar expressions
1/(x^2-2)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2+2)
How do you 1/(x^2+2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ------ 2 x + 2
$$\frac{1}{x^{2} + 2}$$
1/(x^2 + 2)
Fraction decomposition
[src]
1/(2 + x^2)
$$\frac{1}{x^{2} + 2}$$
1 ------ 2 2 + x
Numerical answer
[src]
1/(2.0 + x^2)
1/(2.0 + x^2)