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How to use it?
How do you in partial fractions?
:
(a^2+a*b)/(a+b)
2*(-1+4*x^2/(1+x^2))/(1+x^2)^2
((25*x^2)-1)/((25*x^2)-10*x+1)
(1-x/(1+x))/(1+x)^3
Factor polynomial
:
c^2-9
z^2-0.49
-y^3-5*x^2*y+x^4+5*x^4-7*x^2*y+6*y^3
x^2-x-6
Least common denominator
:
(2*a+b)/(a^2-b^2)+1/(a+b)
(x*sqrt(4*x^2-1))/2-log(4*sqrt(4*x^2-1)+8*x)/4
sin(2*x-y)*cos(y-3*x/2)-2*cot(pi/2-y)*cos(pi/2+y)*sin(y-3*pi/2)
(z/x-z+x+z/z)/x/x^2-z^2
Factor squared
:
-y^4+9*y^2-3
x^2+x+5
y^4-9*y^2+10
-y^4+9*y^2-1
Graphing y =
:
1/(x^4+1)
Integral of d{x}
:
1/(x^4+1)
Identical expressions
one /(x^ four + one)
1 divide by (x to the power of 4 plus 1)
one divide by (x to the power of four plus one)
1/(x4+1)
1/x4+1
1/(x⁴+1)
1/x^4+1
1 divide by (x^4+1)
Similar expressions
1/(x^4-1)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^4+1)
How do you 1/(x^4+1) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ------ 4 x + 1
$$\frac{1}{x^{4} + 1}$$
1/(x^4 + 1)
Fraction decomposition
[src]
1/(1 + x^4)
$$\frac{1}{x^{4} + 1}$$
1 ------ 4 1 + x
Numerical answer
[src]
1/(1.0 + x^4)
1/(1.0 + x^4)