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How do you 1/(x-2)^2 in partial fractions?

An expression to simplify:

The solution

You have entered [src]
   1    
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       2
(x - 2) 
$$\frac{1}{\left(x - 2\right)^{2}}$$
1/((x - 2)^2)
Fraction decomposition [src]
(-2 + x)^(-2)
$$\frac{1}{\left(x - 2\right)^{2}}$$
    1    
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        2
(-2 + x) 
Numerical answer [src]
0.25/(-1 + 0.5*x)^2
0.25/(-1 + 0.5*x)^2
Common denominator [src]
     1      
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     2      
4 + x  - 4*x
$$\frac{1}{x^{2} - 4 x + 4}$$
1/(4 + x^2 - 4*x)