Mister Exam

Lang:

How to use it?
How do you in partial fractions?:
x^2-9/(x+3)^2
(C^2-5c)/(c^2-25)
(9*a^2-16)*(1*(3*a-4)-1/(3*a+4))
(x-6)/(x^2+36)
Factor polynomial:
x^3+y^3+z^3
x^3-8*x^2-23*x+210
x^3-6*x*y+y^3
-x^3+6*x-4*x-8
Least common denominator:
tan((x-pi)/4)-tan((x+pi)/4)
(n*n-2*n)/(n+1)-(n*n-1)/(n+2)
n+6/(4*n+8)-n+2/(4*n-8)+5/(n^2-4)
n+3/(2*n+2)-n+1/(2*n-2)+3/(n^2-1)
Factor squared:
x^2+9*x-6
x^2+5*x+7
-x^2+4*x*y-y^2
-x^2-5*x+14
Identical expressions
(nine *a^ two - sixteen)*(one *(three *a- four)- one /(three *a+ four))
(9 multiply by a squared minus 16) multiply by (1 multiply by (3 multiply by a minus 4) minus 1 divide by (3 multiply by a plus 4))
(nine multiply by a to the power of two minus sixteen) multiply by (one multiply by (three multiply by a minus four) minus one divide by (three multiply by a plus four))
(9*a2-16)*(1*(3*a-4)-1/(3*a+4))
9*a2-16*1*3*a-4-1/3*a+4
(9*a²-16)*(1*(3*a-4)-1/(3*a+4))
(9*a to the power of 2-16)*(1*(3*a-4)-1/(3*a+4))
(9a^2-16)(1(3a-4)-1/(3a+4))
(9a2-16)(1(3a-4)-1/(3a+4))
9a2-1613a-4-1/3a+4
9a^2-1613a-4-1/3a+4
(9*a^2-16)*(1*(3*a-4)-1 divide by (3*a+4))
Similar expressions
(9*a^2+16)*(1*(3*a-4)-1/(3*a+4))
(9*a^2-16)*(1*(3*a-4)-1/(3*a-4))
(9*a^2-16)*(1*(3*a+4)-1/(3*a+4))
(9*a^2-16)*(1*(3*a-4)+1/(3*a+4))

How do you (9a^2-16)(1(3a-4)-1/(3*a+4)) in partial fractions?

You have entered [src]

/   2     \ /             1   \
\9*a  - 16/*|3*a - 4 - -------|
            \          3*a + 4/

$$\left(9 a^{2} - 16\right) \left(\left(3 a - 4\right) - \frac{1}{3 a + 4}\right)$$

(9*a^2 - 16)*(3*a - 4 - 1/(3*a + 4))

Fraction decomposition [src]

68 - 51*a - 36*a^2 + 27*a^3

$$27 a^{3} - 36 a^{2} - 51 a + 68$$

                2       3
68 - 51*a - 36*a  + 27*a

General simplification [src]

                2       3
68 - 51*a - 36*a  + 27*a

$$27 a^{3} - 36 a^{2} - 51 a + 68$$

68 - 51*a - 36*a^2 + 27*a^3

Numerical answer [src]

(-16.0 + 9.0*a^2)*(-4.0 - 1/(4.0 + 3.0*a) + 3.0*a)

(-16.0 + 9.0*a^2)*(-4.0 - 1/(4.0 + 3.0*a) + 3.0*a)

Combinatorics [src]

/         2\           
\-17 + 9*a /*(-4 + 3*a)

$$\left(3 a - 4\right) \left(9 a^{2} - 17\right)$$

(-17 + 9*a^2)*(-4 + 3*a)

Assemble expression [src]

/         2\ /        1         \
\-16 + 9*a /*|-4 - ------- + 3*a|
             \     4 + 3*a      /

$$\left(9 a^{2} - 16\right) \left(3 a - 4 - \frac{1}{3 a + 4}\right)$$

(-16 + 9*a^2)*(-4 - 1/(4 + 3*a) + 3*a)

Common denominator [src]

                2       3
68 - 51*a - 36*a  + 27*a

$$27 a^{3} - 36 a^{2} - 51 a + 68$$

68 - 51*a - 36*a^2 + 27*a^3

Combining rational expressions [src]

                            /         2\
(-1 + (-4 + 3*a)*(4 + 3*a))*\-16 + 9*a /
----------------------------------------
                4 + 3*a

$$\frac{\left(9 a^{2} - 16\right) \left(\left(3 a - 4\right) \left(3 a + 4\right) - 1\right)}{3 a + 4}$$

(-1 + (-4 + 3*a)*(4 + 3*a))*(-16 + 9*a^2)/(4 + 3*a)

Trigonometric part [src]

/         2\ /        1         \
\-16 + 9*a /*|-4 - ------- + 3*a|
             \     4 + 3*a      /

$$\left(9 a^{2} - 16\right) \left(3 a - 4 - \frac{1}{3 a + 4}\right)$$

(-16 + 9*a^2)*(-4 - 1/(4 + 3*a) + 3*a)

Powers [src]

/         2\ /        1         \
\-16 + 9*a /*|-4 - ------- + 3*a|
             \     4 + 3*a      /

$$\left(9 a^{2} - 16\right) \left(3 a - 4 - \frac{1}{3 a + 4}\right)$$

(-16 + 9*a^2)*(-4 - 1/(4 + 3*a) + 3*a)

Rational denominator [src]

                            /         2\
(-1 + (-4 + 3*a)*(4 + 3*a))*\-16 + 9*a /
----------------------------------------
                4 + 3*a

$$\frac{\left(9 a^{2} - 16\right) \left(\left(3 a - 4\right) \left(3 a + 4\right) - 1\right)}{3 a + 4}$$

(-1 + (-4 + 3*a)*(4 + 3*a))*(-16 + 9*a^2)/(4 + 3*a)

How do you (9*a^2-16)*(1*(3*a-4)-1/(3*a+4)) in partial fractions?