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How to use it?
How do you in partial fractions?
:
(2x-1)/(x*(x+2)^2*(x-4))
(z*z-1/2*z)/(z*z-z+1)*z/(z-1/2)
(m^2-1)/(m+1)
1/(2*x^2)
Factor polynomial
:
x^3+y^3
x^2-3*x+2
x^3-x^2-x-2
x^3-x^2-x^3+2
Least common denominator
:
x^4/4+5*x^2/2-4*x
(pi*a^2+pi/4)/(pi*a^2+pi/2)
(a+4)*a/2+(4*a+16)/(4*a^2+a^3)
(5/s)*(2/((1/5)*s+1))*(1/(s+1))
Factor squared
:
-y^4-y^2-3
y^4+y^2+6
x^2+3*x+4
-y^4-y^2+4
Identical expressions
(m^ two - one)/(m+ one)
(m squared minus 1) divide by (m plus 1)
(m to the power of two minus one) divide by (m plus one)
(m2-1)/(m+1)
m2-1/m+1
(m²-1)/(m+1)
(m to the power of 2-1)/(m+1)
m^2-1/m+1
(m^2-1) divide by (m+1)
Similar expressions
(m^2+1)/(m+1)
(m^2-1)/(m-1)
Expression simplification
/
Fraction Decomposition into the simple
/
(m^2-1)/(m+1)
How do you (m^2-1)/(m+1) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
2 m - 1 ------ m + 1
$$\frac{m^{2} - 1}{m + 1}$$
(m^2 - 1)/(m + 1)
Fraction decomposition
[src]
-1 + m
$$m - 1$$
-1 + m
General simplification
[src]
-1 + m
$$m - 1$$
-1 + m
Common denominator
[src]
-1 + m
$$m - 1$$
-1 + m
Numerical answer
[src]
(-1.0 + m^2)/(1.0 + m)
(-1.0 + m^2)/(1.0 + m)
Combinatorics
[src]
-1 + m
$$m - 1$$
-1 + m
