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How do you b^9*b^7*b^2/(b^3*b^(1^9)*b^8) in partial fractions?

An expression to simplify:

The solution

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 9  7  2
b *b *b 
--------
 3  1  8
b *b *b 
$$\frac{b^{2} b^{7} b^{9}}{b^{8} b^{1} b^{3}}$$
((b^9*b^7)*b^2)/(((b^3*b^1)*b^8))
Fraction decomposition [src]
b^6
$$b^{6}$$
 6
b 
General simplification [src]
 6
b 
$$b^{6}$$
b^6
Numerical answer [src]
b^6
b^6
Combining rational expressions [src]
 6
b 
$$b^{6}$$
b^6
Assemble expression [src]
 6
b 
$$b^{6}$$
b^6
Combinatorics [src]
 6
b 
$$b^{6}$$
b^6
Expand expression [src]
 6
b 
$$b^{6}$$
b^6
Rational denominator [src]
 6
b 
$$b^{6}$$
b^6
Common denominator [src]
 6
b 
$$b^{6}$$
b^6
Powers [src]
 6
b 
$$b^{6}$$
b^6
Trigonometric part [src]
 6
b 
$$b^{6}$$
b^6