Mister Exam

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How to use it?
How do you in partial fractions?:
-16/(x-3)+(x^2+7)/(x-3)
y/(y+3)+y/3+2/y
(x^2-12)/(x-3)-x/(3-x)
1/(x^4-1)
Factor polynomial:
x^2+x^2
m^2-n^2
x^2-16
m^2+m-2
Least common denominator:
(z/b+b/z)/z^2+b^(2/7)*z^(16*b)
(z^5-5*z^3+10*z-10/z+5/z^3-1/z^5)*(z^3-3*z+3/z-1/z^3)
z/4*(x-y)-2*z/x-y
(z-3)/(z+3)*(z+(z^2)/(3-z))
Factor squared:
-y^4+9*y^2-3
-y^4-9*y^2+15
y^4-8*y^2-9
-y^4-8*y^2+7
Identical expressions
- sixteen /(x- three)+(x^ two + seven)/(x- three)
minus 16 divide by (x minus 3) plus (x squared plus 7) divide by (x minus 3)
minus sixteen divide by (x minus three) plus (x to the power of two plus seven) divide by (x minus three)
-16/(x-3)+(x2+7)/(x-3)
-16/x-3+x2+7/x-3
-16/(x-3)+(x²+7)/(x-3)
-16/(x-3)+(x to the power of 2+7)/(x-3)
-16/x-3+x^2+7/x-3
-16 divide by (x-3)+(x^2+7) divide by (x-3)
Similar expressions
-16/(x+3)+(x^2+7)/(x-3)
16/(x-3)+(x^2+7)/(x-3)
-16/(x-3)+(x^2-7)/(x-3)
-16/(x-3)-(x^2+7)/(x-3)
-16/(x-3)+(x^2+7)/(x+3)

How do you -16/(x-3)+(x^2+7)/(x-3) in partial fractions?

You have entered [src]

           2    
    16    x  + 7
- ----- + ------
  x - 3   x - 3

$$\frac{x^{2} + 7}{x - 3} - \frac{16}{x - 3}$$

-16/(x - 3) + (x^2 + 7)/(x - 3)

General simplification [src]

3 + x

$$x + 3$$

3 + x

Fraction decomposition [src]

3 + x

$$x + 3$$

3 + x

Numerical answer [src]

-16.0/(-3.0 + x) + (7.0 + x^2)/(-3.0 + x)

-16.0/(-3.0 + x) + (7.0 + x^2)/(-3.0 + x)

Rational denominator [src]

      2
-9 + x 
-------
 -3 + x

$$\frac{x^{2} - 9}{x - 3}$$

(-9 + x^2)/(-3 + x)

Common denominator [src]

3 + x

$$x + 3$$

3 + x

Combinatorics [src]

3 + x

$$x + 3$$

3 + x

Combining rational expressions [src]

      2
-9 + x 
-------
 -3 + x

$$\frac{x^{2} - 9}{x - 3}$$

(-9 + x^2)/(-3 + x)