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x^(-2)

Limit of the function x^(-2)

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The solution

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     1 
 lim --
x->oo 2
     x 
limx1x2\lim_{x \to \infty} \frac{1}{x^{2}}
Limit(x^(-2), x, oo, dir='-')
Detail solution
Let's take the limit
limx1x2\lim_{x \to \infty} \frac{1}{x^{2}}
Let's divide numerator and denominator by x^2:
limx1x2\lim_{x \to \infty} \frac{1}{x^{2}} =
limx(1x2)\lim_{x \to \infty}\left(\frac{1}{x^{2}}\right)
Do Replacement
u=1xu = \frac{1}{x}
then
limx(1x2)=limu0+u2\lim_{x \to \infty}\left(\frac{1}{x^{2}}\right) = \lim_{u \to 0^+} u^{2}
=
02=00^{2} = 0

The final answer:
limx1x2=0\lim_{x \to \infty} \frac{1}{x^{2}} = 0
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
02468-8-6-4-2-10100100
Rapid solution [src]
0
00
Other limits x→0, -oo, +oo, 1
limx1x2=0\lim_{x \to \infty} \frac{1}{x^{2}} = 0
limx01x2=\lim_{x \to 0^-} \frac{1}{x^{2}} = \infty
More at x→0 from the left
limx0+1x2=\lim_{x \to 0^+} \frac{1}{x^{2}} = \infty
More at x→0 from the right
limx11x2=1\lim_{x \to 1^-} \frac{1}{x^{2}} = 1
More at x→1 from the left
limx1+1x2=1\lim_{x \to 1^+} \frac{1}{x^{2}} = 1
More at x→1 from the right
limx1x2=0\lim_{x \to -\infty} \frac{1}{x^{2}} = 0
More at x→-oo
The graph
Limit of the function x^(-2)