$$\lim_{x \to \infty}\left(x \sqrt{x^{2} + 1}\right) = \infty$$ $$\lim_{x \to 0^-}\left(x \sqrt{x^{2} + 1}\right) = 0$$ More at x→0 from the left $$\lim_{x \to 0^+}\left(x \sqrt{x^{2} + 1}\right) = 0$$ More at x→0 from the right $$\lim_{x \to 1^-}\left(x \sqrt{x^{2} + 1}\right) = \sqrt{2}$$ More at x→1 from the left $$\lim_{x \to 1^+}\left(x \sqrt{x^{2} + 1}\right) = \sqrt{2}$$ More at x→1 from the right $$\lim_{x \to -\infty}\left(x \sqrt{x^{2} + 1}\right) = -\infty$$ More at x→-oo