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2+x^2

Limit of the function 2+x^2

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     /     2\
 lim \2 + x /
x->2+        
$$\lim_{x \to 2^+}\left(x^{2} + 2\right)$$
Limit(2 + x^2, x, 2)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
One‐sided limits [src]
     /     2\
 lim \2 + x /
x->2+        
$$\lim_{x \to 2^+}\left(x^{2} + 2\right)$$
6
$$6$$
= 6.0
     /     2\
 lim \2 + x /
x->2-        
$$\lim_{x \to 2^-}\left(x^{2} + 2\right)$$
6
$$6$$
= 6.0
= 6.0
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to 2^-}\left(x^{2} + 2\right) = 6$$
More at x→2 from the left
$$\lim_{x \to 2^+}\left(x^{2} + 2\right) = 6$$
$$\lim_{x \to \infty}\left(x^{2} + 2\right) = \infty$$
More at x→oo
$$\lim_{x \to 0^-}\left(x^{2} + 2\right) = 2$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(x^{2} + 2\right) = 2$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(x^{2} + 2\right) = 3$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(x^{2} + 2\right) = 3$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(x^{2} + 2\right) = \infty$$
More at x→-oo
Rapid solution [src]
6
$$6$$
Numerical answer [src]
6.0
6.0
The graph
Limit of the function 2+x^2