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Limit of the function
:
Limit of (1-3*x^2+2*x^3)/(x^3+2*x+4*x^2)
Limit of (-4-7*x+2*x^2)/(4-13*x+3*x^2)
Limit of 5+3*n
Limit of (-12+x^2-4*x)/(48+x^2-14*x)
Derivative of
:
2/x^3
Integral of d{x}
:
2/x^3
Identical expressions
two /x^ three
2 divide by x cubed
two divide by x to the power of three
2/x3
2/x³
2/x to the power of 3
2 divide by x^3
Similar expressions
(-9+x^2)/(x^3-x^2-6*x)
x^2/(x^3+3*x)
Limit of the function
/
2/x^3
Limit of the function 2/x^3
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
/2 \ lim |--| x->oo| 3| \x /
$$\lim_{x \to \infty}\left(\frac{2}{x^{3}}\right)$$
Limit(2/(x^3), x, oo, dir='-')
Detail solution
Let's take the limit
$$\lim_{x \to \infty}\left(\frac{2}{x^{3}}\right)$$
Let's divide numerator and denominator by x^3:
$$\lim_{x \to \infty}\left(\frac{2}{x^{3}}\right)$$ =
$$\lim_{x \to \infty}\left(\frac{2 \frac{1}{x^{3}}}{1}\right)$$
Do Replacement
$$u = \frac{1}{x}$$
then
$$\lim_{x \to \infty}\left(\frac{2 \frac{1}{x^{3}}}{1}\right) = \lim_{u \to 0^+}\left(2 u^{3}\right)$$
=
$$2 \cdot 0^{3} = 0$$
The final answer:
$$\lim_{x \to \infty}\left(\frac{2}{x^{3}}\right) = 0$$
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Plot the graph
Rapid solution
[src]
0
$$0$$
Expand and simplify
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to \infty}\left(\frac{2}{x^{3}}\right) = 0$$
$$\lim_{x \to 0^-}\left(\frac{2}{x^{3}}\right) = -\infty$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(\frac{2}{x^{3}}\right) = \infty$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(\frac{2}{x^{3}}\right) = 2$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(\frac{2}{x^{3}}\right) = 2$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(\frac{2}{x^{3}}\right) = 0$$
More at x→-oo
The graph