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2/x^4

Limit of the function 2/x^4

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     /2 \
 lim |--|
x->oo| 4|
     \x /
limx(2x4)\lim_{x \to \infty}\left(\frac{2}{x^{4}}\right)
Limit(2/x^4, x, oo, dir='-')
Detail solution
Let's take the limit
limx(2x4)\lim_{x \to \infty}\left(\frac{2}{x^{4}}\right)
Let's divide numerator and denominator by x^4:
limx(2x4)\lim_{x \to \infty}\left(\frac{2}{x^{4}}\right) =
limx(21x41)\lim_{x \to \infty}\left(\frac{2 \frac{1}{x^{4}}}{1}\right)
Do Replacement
u=1xu = \frac{1}{x}
then
limx(21x41)=limu0+(2u4)\lim_{x \to \infty}\left(\frac{2 \frac{1}{x^{4}}}{1}\right) = \lim_{u \to 0^+}\left(2 u^{4}\right)
=
204=02 \cdot 0^{4} = 0

The final answer:
limx(2x4)=0\lim_{x \to \infty}\left(\frac{2}{x^{4}}\right) = 0
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
02468-8-6-4-2-1010020000
Rapid solution [src]
0
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Other limits x→0, -oo, +oo, 1
limx(2x4)=0\lim_{x \to \infty}\left(\frac{2}{x^{4}}\right) = 0
limx0(2x4)=\lim_{x \to 0^-}\left(\frac{2}{x^{4}}\right) = \infty
More at x→0 from the left
limx0+(2x4)=\lim_{x \to 0^+}\left(\frac{2}{x^{4}}\right) = \infty
More at x→0 from the right
limx1(2x4)=2\lim_{x \to 1^-}\left(\frac{2}{x^{4}}\right) = 2
More at x→1 from the left
limx1+(2x4)=2\lim_{x \to 1^+}\left(\frac{2}{x^{4}}\right) = 2
More at x→1 from the right
limx(2x4)=0\lim_{x \to -\infty}\left(\frac{2}{x^{4}}\right) = 0
More at x→-oo
The graph
Limit of the function 2/x^4