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Limit of the function sqrt(2)

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 lim \/ 2 
x->0+     
$$\lim_{x \to 0^+} \sqrt{2}$$
Limit(sqrt(2), x, 0)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to 0^-} \sqrt{2} = \sqrt{2}$$
More at x→0 from the left
$$\lim_{x \to 0^+} \sqrt{2} = \sqrt{2}$$
$$\lim_{x \to \infty} \sqrt{2} = \sqrt{2}$$
More at x→oo
$$\lim_{x \to 1^-} \sqrt{2} = \sqrt{2}$$
More at x→1 from the left
$$\lim_{x \to 1^+} \sqrt{2} = \sqrt{2}$$
More at x→1 from the right
$$\lim_{x \to -\infty} \sqrt{2} = \sqrt{2}$$
More at x→-oo
Rapid solution [src]
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\/ 2 
$$\sqrt{2}$$
One‐sided limits [src]
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 lim \/ 2 
x->0+     
$$\lim_{x \to 0^+} \sqrt{2}$$
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\/ 2 
$$\sqrt{2}$$
= 1.4142135623731
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 lim \/ 2 
x->0-     
$$\lim_{x \to 0^-} \sqrt{2}$$
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\/ 2 
$$\sqrt{2}$$
= 1.4142135623731
= 1.4142135623731
Numerical answer [src]
1.4142135623731
1.4142135623731