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sin(2*x)^2

Limit of the function sin(2*x)^2

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        2     
 lim sin (2*x)
x->0+         
limx0+sin2(2x)\lim_{x \to 0^+} \sin^{2}{\left(2 x \right)}
Limit(sin(2*x)^2, x, 0)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
02468-8-6-4-2-10102-1
Other limits x→0, -oo, +oo, 1
limx0sin2(2x)=0\lim_{x \to 0^-} \sin^{2}{\left(2 x \right)} = 0
More at x→0 from the left
limx0+sin2(2x)=0\lim_{x \to 0^+} \sin^{2}{\left(2 x \right)} = 0
limxsin2(2x)=0,1\lim_{x \to \infty} \sin^{2}{\left(2 x \right)} = \left\langle 0, 1\right\rangle
More at x→oo
limx1sin2(2x)=sin2(2)\lim_{x \to 1^-} \sin^{2}{\left(2 x \right)} = \sin^{2}{\left(2 \right)}
More at x→1 from the left
limx1+sin2(2x)=sin2(2)\lim_{x \to 1^+} \sin^{2}{\left(2 x \right)} = \sin^{2}{\left(2 \right)}
More at x→1 from the right
limxsin2(2x)=0,1\lim_{x \to -\infty} \sin^{2}{\left(2 x \right)} = \left\langle 0, 1\right\rangle
More at x→-oo
One‐sided limits [src]
        2     
 lim sin (2*x)
x->0+         
limx0+sin2(2x)\lim_{x \to 0^+} \sin^{2}{\left(2 x \right)}
0
00
= -4.09486924217481e-30
        2     
 lim sin (2*x)
x->0-         
limx0sin2(2x)\lim_{x \to 0^-} \sin^{2}{\left(2 x \right)}
0
00
= -4.09486924217481e-30
= -4.09486924217481e-30
Rapid solution [src]
0
00
Numerical answer [src]
-4.09486924217481e-30
-4.09486924217481e-30
The graph
Limit of the function sin(2*x)^2