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Limit of the function/ sin(t)

Limit of the function sin(t)

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The solution

You have entered [src] 
 lim sin(t)
t->0+
lim⁡t→0+sin⁡(t)\lim_{t \to 0^+} \sin{\left(t \right)} 
Limit(sin(t), t, 0)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
02468-8-6-4-2-10102-2
Plot the graph
Rapid solution [src] 
0
00
Expand and simplify
One‐sided limits [src] 
 lim sin(t)
t->0+
lim⁡t→0+sin⁡(t)\lim_{t \to 0^+} \sin{\left(t \right)} 
0
00 
= -4.45672020878568e-32
 lim sin(t)
t->0-
lim⁡t→0−sin⁡(t)\lim_{t \to 0^-} \sin{\left(t \right)} 
0
00 
= 4.45672020878568e-32
= 4.45672020878568e-32
Other limits t→0, -oo, +oo, 1
lim⁡t→0−sin⁡(t)=0\lim_{t \to 0^-} \sin{\left(t \right)} = 0
More at t→0 from the left
lim⁡t→0+sin⁡(t)=0\lim_{t \to 0^+} \sin{\left(t \right)} = 0
lim⁡t→∞sin⁡(t)=⟨−1,1⟩\lim_{t \to \infty} \sin{\left(t \right)} = \left\langle -1, 1\right\rangle
More at t→oo
lim⁡t→1−sin⁡(t)=sin⁡(1)\lim_{t \to 1^-} \sin{\left(t \right)} = \sin{\left(1 \right)}
More at t→1 from the left
lim⁡t→1+sin⁡(t)=sin⁡(1)\lim_{t \to 1^+} \sin{\left(t \right)} = \sin{\left(1 \right)}
More at t→1 from the right
lim⁡t→−∞sin⁡(t)=⟨−1,1⟩\lim_{t \to -\infty} \sin{\left(t \right)} = \left\langle -1, 1\right\rangle
More at t→-oo
Numerical answer [src] 
-4.45672020878568e-32
-4.45672020878568e-32
The graph
Limit of the function sin(t)
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