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sin(7*x)/tan(3*x)^2
  • How to use it?

  • Limit of the function:
  • Limit of (1-log(7*x))^(7*x) Limit of (1-log(7*x))^(7*x)
  • Limit of (1+n)*(3+n)/(n*(2+n)) Limit of (1+n)*(3+n)/(n*(2+n))
  • Limit of (1+n)/(2+n) Limit of (1+n)/(2+n)
  • Limit of (1-7/x)^x Limit of (1-7/x)^x
  • Identical expressions

  • sin(seven *x)/tan(three *x)^ two
  • sinus of (7 multiply by x) divide by tangent of (3 multiply by x) squared
  • sinus of (seven multiply by x) divide by tangent of (three multiply by x) to the power of two
  • sin(7*x)/tan(3*x)2
  • sin7*x/tan3*x2
  • sin(7*x)/tan(3*x)²
  • sin(7*x)/tan(3*x) to the power of 2
  • sin(7x)/tan(3x)^2
  • sin(7x)/tan(3x)2
  • sin7x/tan3x2
  • sin7x/tan3x^2
  • sin(7*x) divide by tan(3*x)^2

Limit of the function sin(7*x)/tan(3*x)^2

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The solution

You have entered [src]
     / sin(7*x)\
 lim |---------|
x->0+|   2     |
     \tan (3*x)/
limx0+(sin(7x)tan2(3x))\lim_{x \to 0^+}\left(\frac{\sin{\left(7 x \right)}}{\tan^{2}{\left(3 x \right)}}\right)
Limit(sin(7*x)/(tan(3*x)^2), x, 0)
Lopital's rule
We have indeterminateness of type
0/0,

i.e. limit for the numerator is
limx0+sin(7x)=0\lim_{x \to 0^+} \sin{\left(7 x \right)} = 0
and limit for the denominator is
limx0+tan2(3x)=0\lim_{x \to 0^+} \tan^{2}{\left(3 x \right)} = 0
Let's take derivatives of the numerator and denominator until we eliminate indeterninateness.
limx0+(sin(7x)tan2(3x))\lim_{x \to 0^+}\left(\frac{\sin{\left(7 x \right)}}{\tan^{2}{\left(3 x \right)}}\right)
=
Let's transform the function under the limit a few
limx0+(sin(7x)tan2(3x))\lim_{x \to 0^+}\left(\frac{\sin{\left(7 x \right)}}{\tan^{2}{\left(3 x \right)}}\right)
=
limx0+(ddxsin(7x)ddxtan2(3x))\lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \sin{\left(7 x \right)}}{\frac{d}{d x} \tan^{2}{\left(3 x \right)}}\right)
=
limx0+(7cos(7x)(6tan2(3x)+6)tan(3x))\lim_{x \to 0^+}\left(\frac{7 \cos{\left(7 x \right)}}{\left(6 \tan^{2}{\left(3 x \right)} + 6\right) \tan{\left(3 x \right)}}\right)
=
limx0+(76tan(3x))\lim_{x \to 0^+}\left(\frac{7}{6 \tan{\left(3 x \right)}}\right)
=
limx0+(76tan(3x))\lim_{x \to 0^+}\left(\frac{7}{6 \tan{\left(3 x \right)}}\right)
=
\infty
It can be seen that we have applied Lopital's rule (we have taken derivatives with respect to the numerator and denominator) 1 time(s)
The graph
02468-8-6-4-2-1010-50005000
Rapid solution [src]
oo
\infty
Other limits x→0, -oo, +oo, 1
limx0(sin(7x)tan2(3x))=\lim_{x \to 0^-}\left(\frac{\sin{\left(7 x \right)}}{\tan^{2}{\left(3 x \right)}}\right) = \infty
More at x→0 from the left
limx0+(sin(7x)tan2(3x))=\lim_{x \to 0^+}\left(\frac{\sin{\left(7 x \right)}}{\tan^{2}{\left(3 x \right)}}\right) = \infty
limx(sin(7x)tan2(3x))=,\lim_{x \to \infty}\left(\frac{\sin{\left(7 x \right)}}{\tan^{2}{\left(3 x \right)}}\right) = \left\langle -\infty, \infty\right\rangle
More at x→oo
limx1(sin(7x)tan2(3x))=sin(7)tan2(3)\lim_{x \to 1^-}\left(\frac{\sin{\left(7 x \right)}}{\tan^{2}{\left(3 x \right)}}\right) = \frac{\sin{\left(7 \right)}}{\tan^{2}{\left(3 \right)}}
More at x→1 from the left
limx1+(sin(7x)tan2(3x))=sin(7)tan2(3)\lim_{x \to 1^+}\left(\frac{\sin{\left(7 x \right)}}{\tan^{2}{\left(3 x \right)}}\right) = \frac{\sin{\left(7 \right)}}{\tan^{2}{\left(3 \right)}}
More at x→1 from the right
limx(sin(7x)tan2(3x))=,\lim_{x \to -\infty}\left(\frac{\sin{\left(7 x \right)}}{\tan^{2}{\left(3 x \right)}}\right) = \left\langle -\infty, \infty\right\rangle
More at x→-oo
One‐sided limits [src]
     / sin(7*x)\
 lim |---------|
x->0+|   2     |
     \tan (3*x)/
limx0+(sin(7x)tan2(3x))\lim_{x \to 0^+}\left(\frac{\sin{\left(7 x \right)}}{\tan^{2}{\left(3 x \right)}}\right)
oo
\infty
= 117.371490930519
     / sin(7*x)\
 lim |---------|
x->0-|   2     |
     \tan (3*x)/
limx0(sin(7x)tan2(3x))\lim_{x \to 0^-}\left(\frac{\sin{\left(7 x \right)}}{\tan^{2}{\left(3 x \right)}}\right)
-oo
-\infty
= -117.371490930519
= -117.371490930519
Numerical answer [src]
117.371490930519
117.371490930519
The graph
Limit of the function sin(7*x)/tan(3*x)^2