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Limit of the function/ sin(n)

Limit of the function sin(n)

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The solution

You have entered [src] 
 lim sin(n)
n->oo
lim⁡n→∞sin⁡(n)\lim_{n \to \infty} \sin{\left(n \right)} 
Limit(sin(n), n, oo, dir='-')
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
02468-8-6-4-2-10102-2
Plot the graph
Rapid solution [src] 
<-1, 1>
⟨−1,1⟩\left\langle -1, 1\right\rangle
Expand and simplify
Other limits n→0, -oo, +oo, 1
lim⁡n→∞sin⁡(n)=⟨−1,1⟩\lim_{n \to \infty} \sin{\left(n \right)} = \left\langle -1, 1\right\rangle
lim⁡n→0−sin⁡(n)=0\lim_{n \to 0^-} \sin{\left(n \right)} = 0
More at n→0 from the left
lim⁡n→0+sin⁡(n)=0\lim_{n \to 0^+} \sin{\left(n \right)} = 0
More at n→0 from the right
lim⁡n→1−sin⁡(n)=sin⁡(1)\lim_{n \to 1^-} \sin{\left(n \right)} = \sin{\left(1 \right)}
More at n→1 from the left
lim⁡n→1+sin⁡(n)=sin⁡(1)\lim_{n \to 1^+} \sin{\left(n \right)} = \sin{\left(1 \right)}
More at n→1 from the right
lim⁡n→−∞sin⁡(n)=⟨−1,1⟩\lim_{n \to -\infty} \sin{\left(n \right)} = \left\langle -1, 1\right\rangle
More at n→-oo
The graph
Limit of the function sin(n)
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