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7+x
Limit of the function/ 7+x

Limit of the function 7+x

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You have entered [src] 
 lim (7 + x)
x->2+
lim⁡x→2+(x+7)\lim_{x \to 2^+}\left(x + 7\right) 
Limit(7 + x, x, 2)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
-4.0-3.0-2.0-1.04.00.01.02.03.0020
Plot the graph
Rapid solution [src] 
9
99
Expand and simplify
One‐sided limits [src] 
 lim (7 + x)
x->2+
lim⁡x→2+(x+7)\lim_{x \to 2^+}\left(x + 7\right) 
9
99 
= 9.0
 lim (7 + x)
x->2-
lim⁡x→2−(x+7)\lim_{x \to 2^-}\left(x + 7\right) 
9
99 
= 9.0
= 9.0
Other limits x→0, -oo, +oo, 1
lim⁡x→2−(x+7)=9\lim_{x \to 2^-}\left(x + 7\right) = 9
More at x→2 from the left
lim⁡x→2+(x+7)=9\lim_{x \to 2^+}\left(x + 7\right) = 9
lim⁡x→∞(x+7)=∞\lim_{x \to \infty}\left(x + 7\right) = \infty
More at x→oo
lim⁡x→0−(x+7)=7\lim_{x \to 0^-}\left(x + 7\right) = 7
More at x→0 from the left
lim⁡x→0+(x+7)=7\lim_{x \to 0^+}\left(x + 7\right) = 7
More at x→0 from the right
lim⁡x→1−(x+7)=8\lim_{x \to 1^-}\left(x + 7\right) = 8
More at x→1 from the left
lim⁡x→1+(x+7)=8\lim_{x \to 1^+}\left(x + 7\right) = 8
More at x→1 from the right
lim⁡x→−∞(x+7)=−∞\lim_{x \to -\infty}\left(x + 7\right) = -\infty
More at x→-oo
Numerical answer [src] 
9.0
9.0
The graph
Limit of the function 7+x
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