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Limit of the function
:
Limit of -sin(x)+tan(x)
Limit of cos(x)*tan(5*x)
Limit of -1+sqrt(5)-sqrt(2)-2*x
Limit of ((-1+4*x)/(3+4*x))^(2+3*x)
Derivative of
:
9*x^2
Integral of d{x}
:
9*x^2
Graphing y =
:
9*x^2
Identical expressions
nine *x^ two
9 multiply by x squared
nine multiply by x to the power of two
9*x2
9*x²
9*x to the power of 2
9x^2
9x2
Similar expressions
7+6*x+9*x^2/2
(2-x+4*x^2)/(-5+x+9*x^2)
(-8+27*x^3)/(-4+9*x^2)
Limit of the function
/
9*x^2
Limit of the function 9*x^2
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
/ 2\ lim \9*x / x->oo
$$\lim_{x \to \infty}\left(9 x^{2}\right)$$
Limit(9*x^2, x, oo, dir='-')
Detail solution
Let's take the limit
$$\lim_{x \to \infty}\left(9 x^{2}\right)$$
Let's divide numerator and denominator by x^2:
$$\lim_{x \to \infty}\left(9 x^{2}\right)$$ =
$$\lim_{x \to \infty} \frac{1}{\frac{1}{9} \frac{1}{x^{2}}}$$
Do Replacement
$$u = \frac{1}{x}$$
then
$$\lim_{x \to \infty} \frac{1}{\frac{1}{9} \frac{1}{x^{2}}} = \lim_{u \to 0^+}\left(\frac{9}{u^{2}}\right)$$
=
$$\frac{9}{0} = \infty$$
The final answer:
$$\lim_{x \to \infty}\left(9 x^{2}\right) = \infty$$
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Plot the graph
Rapid solution
[src]
oo
$$\infty$$
Expand and simplify
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to \infty}\left(9 x^{2}\right) = \infty$$
$$\lim_{x \to 0^-}\left(9 x^{2}\right) = 0$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(9 x^{2}\right) = 0$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(9 x^{2}\right) = 9$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(9 x^{2}\right) = 9$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(9 x^{2}\right) = \infty$$
More at x→-oo
The graph