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9*x^2

Limit of the function 9*x^2

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     /   2\
 lim \9*x /
x->oo      
$$\lim_{x \to \infty}\left(9 x^{2}\right)$$
Limit(9*x^2, x, oo, dir='-')
Detail solution
Let's take the limit
$$\lim_{x \to \infty}\left(9 x^{2}\right)$$
Let's divide numerator and denominator by x^2:
$$\lim_{x \to \infty}\left(9 x^{2}\right)$$ =
$$\lim_{x \to \infty} \frac{1}{\frac{1}{9} \frac{1}{x^{2}}}$$
Do Replacement
$$u = \frac{1}{x}$$
then
$$\lim_{x \to \infty} \frac{1}{\frac{1}{9} \frac{1}{x^{2}}} = \lim_{u \to 0^+}\left(\frac{9}{u^{2}}\right)$$
=
$$\frac{9}{0} = \infty$$

The final answer:
$$\lim_{x \to \infty}\left(9 x^{2}\right) = \infty$$
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Rapid solution [src]
oo
$$\infty$$
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to \infty}\left(9 x^{2}\right) = \infty$$
$$\lim_{x \to 0^-}\left(9 x^{2}\right) = 0$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(9 x^{2}\right) = 0$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(9 x^{2}\right) = 9$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(9 x^{2}\right) = 9$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(9 x^{2}\right) = \infty$$
More at x→-oo
The graph
Limit of the function 9*x^2