Let's take the limit x→∞lim(−5x2) Let's divide numerator and denominator by x^2: x→∞lim(−5x2) = x→∞lim(−1)51x211 Do Replacement u=x1 then x→∞lim(−1)51x211=u→0+lim(−u25) = −05=−∞
The final answer: x→∞lim(−5x2)=−∞
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type