We have indeterminateness of type
0/0,
i.e. limit for the numerator is
x→0+limsin(x)=0and limit for the denominator is
x→0+limlog(x)1=0Let's take derivatives of the numerator and denominator until we eliminate indeterninateness.
x→0+lim(log(x)sin(x))=
x→0+lim(dxdlog(x)1dxdsin(x))=
x→0+lim(−xlog(x)2cos(x))=
x→0+lim(−xlog(x)2cos(x))=
0It can be seen that we have applied Lopital's rule (we have taken derivatives with respect to the numerator and denominator) 1 time(s)