We have indeterminateness of type
oo/oo,
i.e. limit for the numerator is
n→∞limlog(n)=∞and limit for the denominator is
n→∞limn=∞Let's take derivatives of the numerator and denominator until we eliminate indeterninateness.
n→∞lim(nlog(n))=
n→∞lim(dndndndlog(n))=
n→∞limn1=
n→∞limn1=
0It can be seen that we have applied Lopital's rule (we have taken derivatives with respect to the numerator and denominator) 1 time(s)