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Limit of the function
:
Limit of (-2+x)/(-2+x^2-x)
Limit of cos(5*x)*sin(2*x)/tan(x)
Limit of 3*sin(x)^2/(4*x)
Limit of log(1+e^x)
Derivative of
:
4*x^2
Graphing y =
:
4*x^2
Integral of d{x}
:
4*x^2
Identical expressions
four *x^ two
4 multiply by x squared
four multiply by x to the power of two
4*x2
4*x²
4*x to the power of 2
4x^2
4x2
Similar expressions
x^4/2-4*x^2
(3-7*x^2)/(7+8*x+14*x^2)
4*x^2/(1-cos(4*x))
x/(x-4*x^2)
((-1+4*x)/(3+4*x))^(2*x)
Limit of the function
/
4*x^2
Limit of the function 4*x^2
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
/ 2\ lim \4*x / x->-2+
$$\lim_{x \to -2^+}\left(4 x^{2}\right)$$
Limit(4*x^2, x, -2)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Plot the graph
Rapid solution
[src]
16
$$16$$
Expand and simplify
One‐sided limits
[src]
/ 2\ lim \4*x / x->-2+
$$\lim_{x \to -2^+}\left(4 x^{2}\right)$$
16
$$16$$
= 16.0
/ 2\ lim \4*x / x->-2-
$$\lim_{x \to -2^-}\left(4 x^{2}\right)$$
16
$$16$$
= 16.0
= 16.0
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to -2^-}\left(4 x^{2}\right) = 16$$
More at x→-2 from the left
$$\lim_{x \to -2^+}\left(4 x^{2}\right) = 16$$
$$\lim_{x \to \infty}\left(4 x^{2}\right) = \infty$$
More at x→oo
$$\lim_{x \to 0^-}\left(4 x^{2}\right) = 0$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(4 x^{2}\right) = 0$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(4 x^{2}\right) = 4$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(4 x^{2}\right) = 4$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(4 x^{2}\right) = \infty$$
More at x→-oo
Numerical answer
[src]
16.0
16.0
The graph