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4*x^2

Limit of the function 4*x^2

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      /   2\
 lim  \4*x /
x->-2+      
$$\lim_{x \to -2^+}\left(4 x^{2}\right)$$
Limit(4*x^2, x, -2)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Rapid solution [src]
16
$$16$$
One‐sided limits [src]
      /   2\
 lim  \4*x /
x->-2+      
$$\lim_{x \to -2^+}\left(4 x^{2}\right)$$
16
$$16$$
= 16.0
      /   2\
 lim  \4*x /
x->-2-      
$$\lim_{x \to -2^-}\left(4 x^{2}\right)$$
16
$$16$$
= 16.0
= 16.0
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to -2^-}\left(4 x^{2}\right) = 16$$
More at x→-2 from the left
$$\lim_{x \to -2^+}\left(4 x^{2}\right) = 16$$
$$\lim_{x \to \infty}\left(4 x^{2}\right) = \infty$$
More at x→oo
$$\lim_{x \to 0^-}\left(4 x^{2}\right) = 0$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(4 x^{2}\right) = 0$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(4 x^{2}\right) = 4$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(4 x^{2}\right) = 4$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(4 x^{2}\right) = \infty$$
More at x→-oo
Numerical answer [src]
16.0
16.0
The graph
Limit of the function 4*x^2