Integral of y/2 dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫2ydy=2∫ydy
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The integral of yn is n+1yn+1 when n=−1:
∫ydy=2y2
So, the result is: 4y2
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Add the constant of integration:
4y2+constant
The answer is:
4y2+constant
The answer (Indefinite)
[src]
/
| 2
| y y
| - dy = C + --
| 2 4
|
/
∫2ydy=C+4y2
The graph
Use the examples entering the upper and lower limits of integration.