1 / | | y | ------ dy | log(y) | / 0
Integral(y/log(y), (y, 0, 1))
Let .
Then let and substitute :
EiRule(a=2, b=0, context=exp(2*_u)/_u, symbol=_u)
Now substitute back in:
Add the constant of integration:
The answer is:
/ | | y | ------ dy = C + Ei(2*log(y)) | log(y) | /
Use the examples entering the upper and lower limits of integration.