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1/(sqrt(1+x^2))

Integral of 1/(sqrt(1+x^2)) dx

Limits of integration:

from to
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
  1                 
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0111x2+1dx\int\limits_{0}^{1} 1 \cdot \frac{1}{\sqrt{x^{2} + 1}}\, dx
Integral(1/sqrt(1 + x^2), (x, 0, 1))
Detail solution

    TrigSubstitutionRule(theta=_theta, func=tan(_theta), rewritten=sec(_theta), substep=RewriteRule(rewritten=(tan(_theta)*sec(_theta) + sec(_theta)**2)/(tan(_theta) + sec(_theta)), substep=AlternativeRule(alternatives=[URule(u_var=_u, u_func=tan(_theta) + sec(_theta), constant=1, substep=ReciprocalRule(func=_u, context=1/_u, symbol=_u), context=(tan(_theta)*sec(_theta) + sec(_theta)**2)/(tan(_theta) + sec(_theta)), symbol=_theta)], context=(tan(_theta)*sec(_theta) + sec(_theta)**2)/(tan(_theta) + sec(_theta)), symbol=_theta), context=sec(_theta), symbol=_theta), restriction=True, context=1/sqrt(x**2 + 1), symbol=x)

  1. Add the constant of integration:

    log(x+x2+1)+constant\log{\left(x + \sqrt{x^{2} + 1} \right)}+ \mathrm{constant}


The answer is:

log(x+x2+1)+constant\log{\left(x + \sqrt{x^{2} + 1} \right)}+ \mathrm{constant}

The answer (Indefinite) [src]
  /                                           
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 | 1*----------- dx = C + log\x + \/  1 + x  /
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11x2+1dx=C+log(x+x2+1)\int 1 \cdot \frac{1}{\sqrt{x^{2} + 1}}\, dx = C + \log{\left(x + \sqrt{x^{2} + 1} \right)}
The graph
0.001.000.100.200.300.400.500.600.700.800.9002
The answer [src]
   /      ___\
log\1 + \/ 2 /
log(1+2)\log{\left(1 + \sqrt{2} \right)}
=
=
   /      ___\
log\1 + \/ 2 /
log(1+2)\log{\left(1 + \sqrt{2} \right)}
Numerical answer [src]
0.881373587019543
0.881373587019543
The graph
Integral of 1/(sqrt(1+x^2)) dx

    Use the examples entering the upper and lower limits of integration.