Integral of x^2-16 dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
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The integral of a constant is the constant times the variable of integration:
∫(−16)dx=−16x
The result is: 3x3−16x
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Now simplify:
3x(x2−48)
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Add the constant of integration:
3x(x2−48)+constant
The answer is:
3x(x2−48)+constant
The answer (Indefinite)
[src]
/
| 3
| / 2 \ x
| \x - 16/ dx = C - 16*x + --
| 3
/
∫(x2−16)dx=C+3x3−16x
The graph
Use the examples entering the upper and lower limits of integration.