Integral of x^2-2x+3 dx
The solution
Detail solution
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Integrate term-by-term:
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Integrate term-by-term:
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
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The integral of a constant times a function is the constant times the integral of the function:
∫(−2x)dx=−2∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: −x2
The result is: 3x3−x2
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The integral of a constant is the constant times the variable of integration:
∫3dx=3x
The result is: 3x3−x2+3x
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Now simplify:
3x(x2−3x+9)
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Add the constant of integration:
3x(x2−3x+9)+constant
The answer is:
3x(x2−3x+9)+constant
The answer (Indefinite)
[src]
/
| 3
| / 2 \ 2 x
| \x - 2*x + 3/ dx = C - x + 3*x + --
| 3
/
∫((x2−2x)+3)dx=C+3x3−x2+3x
The graph
Use the examples entering the upper and lower limits of integration.