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x^2-2x-3
Solving integrals/ x^2-2x-3

Integral of x^2-2x-3 dx

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The solution

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∫−13((x2−2x)−3) dx\int\limits_{-1}^{3} \left(\left(x^{2} - 2 x\right) - 3\right)\, dx 
Integral(x^2 - 2*x - 3, (x, -1, 3))
Detail solution

  1. Integrate term-by-term:

    1. Integrate term-by-term:

      1. The integral of xnx^{n} is xn+1n+1\frac{x^{n + 1}}{n + 1} when n≠−1n \neq -1:

        ∫x2 dx=x33\int x^{2}\, dx = \frac{x^{3}}{3}

      1. The integral of a constant times a function is the constant times the integral of the function:

        ∫(−2x) dx=−2∫x dx\int \left(- 2 x\right)\, dx = - 2 \int x\, dx

        1. The integral of xnx^{n} is xn+1n+1\frac{x^{n + 1}}{n + 1} when n≠−1n \neq -1:

          ∫x dx=x22\int x\, dx = \frac{x^{2}}{2}

        So, the result is: −x2- x^{2}

      The result is: x33−x2\frac{x^{3}}{3} - x^{2}

    1. The integral of a constant is the constant times the variable of integration:

      ∫(−3) dx=−3x\int \left(-3\right)\, dx = - 3 x

    The result is: x33−x2−3x\frac{x^{3}}{3} - x^{2} - 3 x

  2. Now simplify:

    x(x2−3x−9)3\frac{x \left(x^{2} - 3 x - 9\right)}{3}

  3. Add the constant of integration:

    x(x2−3x−9)3+constant\frac{x \left(x^{2} - 3 x - 9\right)}{3}+ \mathrm{constant}

The answer is:

x(x2−3x−9)3+constant\frac{x \left(x^{2} - 3 x - 9\right)}{3}+ \mathrm{constant}

The answer (Indefinite) [src] 
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 | \x  - 2*x - 3/ dx = C - x  - 3*x + --
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∫((x2−2x)−3) dx=C+x33−x2−3x\int \left(\left(x^{2} - 2 x\right) - 3\right)\, dx = C + \frac{x^{3}}{3} - x^{2} - 3 x
Simplify
The graph
-1.0-0.53.00.00.51.01.52.02.5-1010
Plot the graph f(x)
The answer [src] 
-32/3
−323- \frac{32}{3} 
=
= 
-32/3
−323- \frac{32}{3} 
-32/3
Numerical answer [src] 
-10.6666666666667
-10.6666666666667
The graph
Integral of x^2-2x-3 dx

    Use the examples entering the upper and lower limits of integration.

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