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(x^3)/3+(sin5x)/5

Integral of (x^3)/3+(sin5x)/5 dx

Limits of integration:

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The graph:

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The solution

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  1                   
  /                   
 |                    
 |  / 3           \   
 |  |x    sin(5*x)|   
 |  |-- + --------| dx
 |  \3       5    /   
 |                    
/                     
0                     
01(x33+sin(5x)5)dx\int\limits_{0}^{1} \left(\frac{x^{3}}{3} + \frac{\sin{\left(5 x \right)}}{5}\right)\, dx
Integral(x^3/3 + sin(5*x)/5, (x, 0, 1))
Detail solution
  1. Integrate term-by-term:

    1. The integral of a constant times a function is the constant times the integral of the function:

      x33dx=x3dx3\int \frac{x^{3}}{3}\, dx = \frac{\int x^{3}\, dx}{3}

      1. The integral of xnx^{n} is xn+1n+1\frac{x^{n + 1}}{n + 1} when n1n \neq -1:

        x3dx=x44\int x^{3}\, dx = \frac{x^{4}}{4}

      So, the result is: x412\frac{x^{4}}{12}

    1. The integral of a constant times a function is the constant times the integral of the function:

      sin(5x)5dx=sin(5x)dx5\int \frac{\sin{\left(5 x \right)}}{5}\, dx = \frac{\int \sin{\left(5 x \right)}\, dx}{5}

      1. Let u=5xu = 5 x.

        Then let du=5dxdu = 5 dx and substitute du5\frac{du}{5}:

        sin(u)25du\int \frac{\sin{\left(u \right)}}{25}\, du

        1. The integral of a constant times a function is the constant times the integral of the function:

          sin(u)5du=sin(u)du5\int \frac{\sin{\left(u \right)}}{5}\, du = \frac{\int \sin{\left(u \right)}\, du}{5}

          1. The integral of sine is negative cosine:

            sin(u)du=cos(u)\int \sin{\left(u \right)}\, du = - \cos{\left(u \right)}

          So, the result is: cos(u)5- \frac{\cos{\left(u \right)}}{5}

        Now substitute uu back in:

        cos(5x)5- \frac{\cos{\left(5 x \right)}}{5}

      So, the result is: cos(5x)25- \frac{\cos{\left(5 x \right)}}{25}

    The result is: x412cos(5x)25\frac{x^{4}}{12} - \frac{\cos{\left(5 x \right)}}{25}

  2. Add the constant of integration:

    x412cos(5x)25+constant\frac{x^{4}}{12} - \frac{\cos{\left(5 x \right)}}{25}+ \mathrm{constant}


The answer is:

x412cos(5x)25+constant\frac{x^{4}}{12} - \frac{\cos{\left(5 x \right)}}{25}+ \mathrm{constant}

The answer (Indefinite) [src]
  /                                      
 |                                       
 | / 3           \                      4
 | |x    sin(5*x)|          cos(5*x)   x 
 | |-- + --------| dx = C - -------- + --
 | \3       5    /             25      12
 |                                       
/                                        
x412cos(5x)25{{x^4}\over{12}}-{{\cos \left(5\,x\right)}\over{25}}
The graph
0.001.000.100.200.300.400.500.600.700.800.900.25-0.25
The answer [src]
 37   cos(5)
--- - ------
300     25  
12cos537300-{{12\,\cos 5-37}\over{300}}
=
=
 37   cos(5)
--- - ------
300     25  
cos(5)25+37300- \frac{\cos{\left(5 \right)}}{25} + \frac{37}{300}
Numerical answer [src]
0.111986845914804
0.111986845914804
The graph
Integral of (x^3)/3+(sin5x)/5 dx

    Use the examples entering the upper and lower limits of integration.