Integral of (x^3)/3+(sin5x)/5 dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫3x3dx=3∫x3dx
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The integral of xn is n+1xn+1 when n=−1:
∫x3dx=4x4
So, the result is: 12x4
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The integral of a constant times a function is the constant times the integral of the function:
∫5sin(5x)dx=5∫sin(5x)dx
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Let u=5x.
Then let du=5dx and substitute 5du:
∫25sin(u)du
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The integral of a constant times a function is the constant times the integral of the function:
∫5sin(u)du=5∫sin(u)du
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The integral of sine is negative cosine:
∫sin(u)du=−cos(u)
So, the result is: −5cos(u)
Now substitute u back in:
−5cos(5x)
So, the result is: −25cos(5x)
The result is: 12x4−25cos(5x)
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Add the constant of integration:
12x4−25cos(5x)+constant
The answer is:
12x4−25cos(5x)+constant
The answer (Indefinite)
[src]
/
|
| / 3 \ 4
| |x sin(5*x)| cos(5*x) x
| |-- + --------| dx = C - -------- + --
| \3 5 / 25 12
|
/
12x4−25cos(5x)
The graph
37 cos(5)
--- - ------
300 25
−30012cos5−37
=
37 cos(5)
--- - ------
300 25
−25cos(5)+30037
Use the examples entering the upper and lower limits of integration.