Integral of x^2sin(x^3)dx dx
The solution
Detail solution
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Let u=x3.
Then let du=3x2dx and substitute 3du:
∫9sin(u)du
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The integral of a constant times a function is the constant times the integral of the function:
∫3sin(u)du=3∫sin(u)du
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The integral of sine is negative cosine:
∫sin(u)du=−cos(u)
So, the result is: −3cos(u)
Now substitute u back in:
−3cos(x3)
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Add the constant of integration:
−3cos(x3)+constant
The answer is:
−3cos(x3)+constant
The answer (Indefinite)
[src]
/
| / 3\
| 2 / 3\ cos\x /
| x *sin\x /*1 dx = C - -------
| 3
/
∫x2sin(x3)1dx=C−3cos(x3)
The graph
31−3cos(1)
=
31−3cos(1)
Use the examples entering the upper and lower limits of integration.