Integral of x*arccos(x) dx
The solution
Detail solution
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Use integration by parts:
∫udv=uv−∫vdu
Let u(x)=acos(x) and let dv(x)=x.
Then du(x)=−1−x21.
To find v(x):
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
Now evaluate the sub-integral.
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The integral of a constant times a function is the constant times the integral of the function:
∫(−21−x2x2)dx=−2∫1−x2x2dx
SqrtQuadraticDenomRule(a=1, b=0, c=-1, coeffs=[1, 0, 0], context=x**2/sqrt(1 - x**2), symbol=x)
So, the result is: 4x1−x2−4asin(x)
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Add the constant of integration:
2x2acos(x)−4x1−x2+4asin(x)+constant
The answer is:
2x2acos(x)−4x1−x2+4asin(x)+constant
The answer (Indefinite)
[src]
________
/ 2 / 2
| asin(x) x *acos(x) x*\/ 1 - x
| x*acos(x) dx = C + ------- + ---------- - -------------
| 4 2 4
/
22arcsinx−2x1−x2+2x2arccosx
The graph
Use the examples entering the upper and lower limits of integration.