Integral of 2*x*e^(-x^2) dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫2xe−x2dx=2∫xe−x2dx
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Let u=e−x2.
Then let du=−2xe−x2dx and substitute −2du:
∫41du
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The integral of a constant times a function is the constant times the integral of the function:
∫(−21)du=−2∫1du
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The integral of a constant is the constant times the variable of integration:
∫1du=u
So, the result is: −2u
Now substitute u back in:
−2e−x2
So, the result is: −e−x2
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Add the constant of integration:
−e−x2+constant
The answer is:
−e−x2+constant
The answer (Indefinite)
[src]
/
|
| 2 2
| -x -x
| 2*x*e dx = C - e
|
/
The graph
2(21−2e−1)
=
−e1+1
Use the examples entering the upper and lower limits of integration.