Integral of 2*sin(x)*cos(x) dx

1. There are multiple ways to do this integral.

   Method #1

   1. Let $u = \sin{\left(x \right)}$.

      Then let $du = \cos{\left(x \right)} dx$ and substitute $2 du$:

      $$\int 2 u\, du$$

      1. The integral of a constant times a function is the constant times the integral of the function:

         $$\int u\, du = 2 \int u\, du$$

         1. The integral of $u^{n}$ is $\frac{u^{n + 1}}{n + 1}$ when $n \neq -1$:

            $$\int u\, du = \frac{u^{2}}{2}$$

         So, the result is: $u^{2}$

      Now substitute $u$ back in:

      $$\sin^{2}{\left(x \right)}$$

   Method #2

   1. Let $u = \cos{\left(x \right)}$.

      Then let $du = - \sin{\left(x \right)} dx$ and substitute $- 2 du$:

      $$\int \left(- 2 u\right)\, du$$

      1. The integral of a constant times a function is the constant times the integral of the function:

         $$\int u\, du = - 2 \int u\, du$$

         1. The integral of $u^{n}$ is $\frac{u^{n + 1}}{n + 1}$ when $n \neq -1$:

            $$\int u\, du = \frac{u^{2}}{2}$$

         So, the result is: $- u^{2}$

      Now substitute $u$ back in:

      $$- \cos^{2}{\left(x \right)}$$

2. Add the constant of integration:

   $$\sin^{2}{\left(x \right)}+ \mathrm{constant}$$

The answer is: