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2*sin(x)*cos(x)

Derivative of 2*sin(x)*cos(x)

Function f() - derivative -N order at the point
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The solution

You have entered [src]
2*sin(x)*cos(x)
2sin(x)cos(x)2 \sin{\left(x \right)} \cos{\left(x \right)}
d                  
--(2*sin(x)*cos(x))
dx                 
ddx2sin(x)cos(x)\frac{d}{d x} 2 \sin{\left(x \right)} \cos{\left(x \right)}
Detail solution
  1. The derivative of a constant times a function is the constant times the derivative of the function.

    1. Apply the product rule:

      ddxf(x)g(x)=f(x)ddxg(x)+g(x)ddxf(x)\frac{d}{d x} f{\left(x \right)} g{\left(x \right)} = f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}

      f(x)=cos(x)f{\left(x \right)} = \cos{\left(x \right)}; to find ddxf(x)\frac{d}{d x} f{\left(x \right)}:

      1. The derivative of cosine is negative sine:

        ddxcos(x)=sin(x)\frac{d}{d x} \cos{\left(x \right)} = - \sin{\left(x \right)}

      g(x)=sin(x)g{\left(x \right)} = \sin{\left(x \right)}; to find ddxg(x)\frac{d}{d x} g{\left(x \right)}:

      1. The derivative of sine is cosine:

        ddxsin(x)=cos(x)\frac{d}{d x} \sin{\left(x \right)} = \cos{\left(x \right)}

      The result is: sin2(x)+cos2(x)- \sin^{2}{\left(x \right)} + \cos^{2}{\left(x \right)}

    So, the result is: 2sin2(x)+2cos2(x)- 2 \sin^{2}{\left(x \right)} + 2 \cos^{2}{\left(x \right)}

  2. Now simplify:

    2cos(2x)2 \cos{\left(2 x \right)}


The answer is:

2cos(2x)2 \cos{\left(2 x \right)}

The graph
02468-8-6-4-2-10105-5
The first derivative [src]
       2           2   
- 2*sin (x) + 2*cos (x)
2sin2(x)+2cos2(x)- 2 \sin^{2}{\left(x \right)} + 2 \cos^{2}{\left(x \right)}
The second derivative [src]
-8*cos(x)*sin(x)
8sin(x)cos(x)- 8 \sin{\left(x \right)} \cos{\left(x \right)}
The third derivative [src]
  /   2         2   \
8*\sin (x) - cos (x)/
8(sin2(x)cos2(x))8 \left(\sin^{2}{\left(x \right)} - \cos^{2}{\left(x \right)}\right)
The graph
Derivative of 2*sin(x)*cos(x)