1 / | | x | 2/3 dx | / 0
Integral((2/3)^x, (x, 0, 1))
The integral of an exponential function is itself divided by the natural logarithm of the base.
Add the constant of integration:
The answer is:
/ | x | x 2/3 | 2/3 dx = C + -------- | log(2/3) /
-1 -------------------- 3*(-log(3) + log(2))
=
-1 -------------------- 3*(-log(3) + log(2))
-1/(3*(-log(3) + log(2)))
Use the examples entering the upper and lower limits of integration.