Integral of 3*exp(-2*x) dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫3e−2xdx=3∫e−2xdx
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Let u=−2x.
Then let du=−2dx and substitute −2du:
∫(−2eu)du
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The integral of a constant times a function is the constant times the integral of the function:
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The integral of the exponential function is itself.
∫eudu=eu
So, the result is: −2eu
Now substitute u back in:
−2e−2x
So, the result is: −23e−2x
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Add the constant of integration:
−23e−2x+constant
The answer is:
−23e−2x+constant
The answer (Indefinite)
[src]
/
| -2*x
| -2*x 3*e
| 3*e dx = C - -------
| 2
/
∫3e−2xdx=C−23e−2x
The graph
23−2e23
=
23−2e23
Use the examples entering the upper and lower limits of integration.