Integral of tg(7x) dx
The solution
Detail solution
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Rewrite the integrand:
tan(7x)=cos(7x)sin(7x)
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There are multiple ways to do this integral.
Method #1
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Let u=cos(7x).
Then let du=−7sin(7x)dx and substitute −7du:
∫(−7u1)du
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The integral of a constant times a function is the constant times the integral of the function:
∫u1du=−7∫u1du
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The integral of u1 is log(u).
So, the result is: −7log(u)
Now substitute u back in:
−7log(cos(7x))
Method #2
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Let u=7x.
Then let du=7dx and substitute 7du:
∫7cos(u)sin(u)du
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The integral of a constant times a function is the constant times the integral of the function:
∫cos(u)sin(u)du=7∫cos(u)sin(u)du
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Let u=cos(u).
Then let du=−sin(u)du and substitute −du:
∫(−u1)du
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The integral of a constant times a function is the constant times the integral of the function:
∫u1du=−∫u1du
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The integral of u1 is log(u).
So, the result is: −log(u)
Now substitute u back in:
−log(cos(u))
So, the result is: −7log(cos(u))
Now substitute u back in:
−7log(cos(7x))
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Add the constant of integration:
−7log(cos(7x))+constant
The answer is:
−7log(cos(7x))+constant
The graph
Use the examples entering the upper and lower limits of integration.