Integral of tag^5xsec^2xdx dx
The solution
Detail solution
-
There are multiple ways to do this integral.
Method #1
-
Let u=tan(x).
Then let du=(tan2(x)+1)dx and substitute du:
∫u5du
-
The integral of un is n+1un+1 when n=−1:
∫u5du=6u6
Now substitute u back in:
6tan6(x)
Method #2
-
Rewrite the integrand:
tan5(x)sec2(x)1=(sec2(x)−1)2tan(x)sec2(x)
-
Let u=sec2(x)−1.
Then let du=2tan(x)sec2(x)dx and substitute 2du:
∫4u2du
-
The integral of a constant times a function is the constant times the integral of the function:
∫2u2du=2∫u2du
-
The integral of un is n+1un+1 when n=−1:
∫u2du=3u3
So, the result is: 6u3
Now substitute u back in:
6(sec2(x)−1)3
-
Add the constant of integration:
6tan6(x)+constant
The answer is:
6tan6(x)+constant
The answer (Indefinite)
[src]
/
| 6
| 5 2 tan (x)
| tan (x)*sec (x)*1 dx = C + -------
| 6
/
6tan6x
The graph
4 2
1 -1 - 3*cos (1) + 3*cos (1)
- - - --------------------------
6 6
6*cos (1)
−6sin61−18sin41+18sin21−61−2sin61−6sin41+6sin21−2sin41+2sin61−6sin41+6sin21−2sin21−61
=
4 2
1 -1 - 3*cos (1) + 3*cos (1)
- - - --------------------------
6 6
6*cos (1)
−61−6cos6(1)−1−3cos4(1)+3cos2(1)
Use the examples entering the upper and lower limits of integration.