Integral of sqrt(2*x+1) dx
The solution
Detail solution
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Let u=2x+1.
Then let du=2dx and substitute 2du:
∫2udu
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The integral of a constant times a function is the constant times the integral of the function:
∫udu=2∫udu
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The integral of un is n+1un+1 when n=−1:
∫udu=32u23
So, the result is: 3u23
Now substitute u back in:
3(2x+1)23
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Now simplify:
3(2x+1)23
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Add the constant of integration:
3(2x+1)23+constant
The answer is:
3(2x+1)23+constant
The answer (Indefinite)
[src]
/
| 3/2
| _________ (2*x + 1)
| \/ 2*x + 1 dx = C + ------------
| 3
/
∫2x+1dx=C+3(2x+1)23
The graph
−31+3
=
−31+3
Use the examples entering the upper and lower limits of integration.