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sqrt(2*x+1)

Integral of sqrt(2*x+1) dx

Limits of integration:

from to
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The graph:

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Piecewise:

The solution

You have entered [src]
  1               
  /               
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 |    _________   
 |  \/ 2*x + 1  dx
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012x+1dx\int\limits_{0}^{1} \sqrt{2 x + 1}\, dx
Integral(sqrt(2*x + 1), (x, 0, 1))
Detail solution
  1. Let u=2x+1u = 2 x + 1.

    Then let du=2dxdu = 2 dx and substitute du2\frac{du}{2}:

    u2du\int \frac{\sqrt{u}}{2}\, du

    1. The integral of a constant times a function is the constant times the integral of the function:

      udu=udu2\int \sqrt{u}\, du = \frac{\int \sqrt{u}\, du}{2}

      1. The integral of unu^{n} is un+1n+1\frac{u^{n + 1}}{n + 1} when n1n \neq -1:

        udu=2u323\int \sqrt{u}\, du = \frac{2 u^{\frac{3}{2}}}{3}

      So, the result is: u323\frac{u^{\frac{3}{2}}}{3}

    Now substitute uu back in:

    (2x+1)323\frac{\left(2 x + 1\right)^{\frac{3}{2}}}{3}

  2. Now simplify:

    (2x+1)323\frac{\left(2 x + 1\right)^{\frac{3}{2}}}{3}

  3. Add the constant of integration:

    (2x+1)323+constant\frac{\left(2 x + 1\right)^{\frac{3}{2}}}{3}+ \mathrm{constant}


The answer is:

(2x+1)323+constant\frac{\left(2 x + 1\right)^{\frac{3}{2}}}{3}+ \mathrm{constant}

The answer (Indefinite) [src]
  /                                 
 |                               3/2
 |   _________          (2*x + 1)   
 | \/ 2*x + 1  dx = C + ------------
 |                           3      
/                                   
2x+1dx=C+(2x+1)323\int \sqrt{2 x + 1}\, dx = C + \frac{\left(2 x + 1\right)^{\frac{3}{2}}}{3}
The graph
0.001.000.100.200.300.400.500.600.700.800.9002
The answer [src]
  1     ___
- - + \/ 3 
  3        
13+3- \frac{1}{3} + \sqrt{3}
=
=
  1     ___
- - + \/ 3 
  3        
13+3- \frac{1}{3} + \sqrt{3}
-1/3 + sqrt(3)
Numerical answer [src]
1.39871747423554
1.39871747423554
The graph
Integral of sqrt(2*x+1) dx

    Use the examples entering the upper and lower limits of integration.