Integral of sqrt(1-x) dx
The solution
Detail solution
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Let u=1−x.
Then let du=−dx and substitute −du:
∫(−u)du
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The integral of a constant times a function is the constant times the integral of the function:
∫udu=−∫udu
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The integral of un is n+1un+1 when n=−1:
∫udu=32u23
So, the result is: −32u23
Now substitute u back in:
−32(1−x)23
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Add the constant of integration:
−32(1−x)23+constant
The answer is:
−32(1−x)23+constant
The answer (Indefinite)
[src]
/
| 3/2
| _______ 2*(1 - x)
| \/ 1 - x dx = C - ------------
| 3
/
∫1−xdx=C−32(1−x)23
The graph
Use the examples entering the upper and lower limits of integration.