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Solving integrals/ sinx/1+cosx

Integral of sinx/1+cosx dx

Limits of integration:

from to
v

The graph:

from to

Piecewise:

The solution

You have entered [src] 
 pi                     
 --                     
 2                      
  /                     
 |                      
 |  /sin(x)         \   
 |  |------ + cos(x)| dx
 |  \  1            /   
 |                      
/                       
0
$$\int\limits_{0}^{\frac{\pi}{2}} \left(\frac{\sin{\left(x \right)}}{1} + \cos{\left(x \right)}\right)\, dx$$ 
Integral(sin(x)/1 + cos(x), (x, 0, pi/2))
Detail solution

  1. Integrate term-by-term:

    1. The integral of a constant times a function is the constant times the integral of the function:

      1. Don't know the steps in finding this integral.

        But the integral is

      So, the result is:

    1. The integral of cosine is sine:

    The result is:

  2. Now simplify:

  3. Add the constant of integration:

The answer is:

The answer (Indefinite) [src] 
  /                                          
 |                                           
 | /sin(x)         \                         
 | |------ + cos(x)| dx = C - cos(x) + sin(x)
 | \  1            /                         
 |                                           
/
$$\int \left(\frac{\sin{\left(x \right)}}{1} + \cos{\left(x \right)}\right)\, dx = C + \sin{\left(x \right)} - \cos{\left(x \right)}$$
Simplify
The graph
Plot the graph f(x)
The answer [src] 
2
$$2$$ 
=
= 
2
$$2$$ 
2
Numerical answer [src] 
2.0
2.0

    Use the examples entering the upper and lower limits of integration.

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