Integral of sin8x dx

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  1            
  /            
 |             
 |  sin(8*x) dx
 |             
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0

$$\int\limits_{0}^{1} \sin{\left(8 x \right)}\, dx$$

Integral(sin(8*x), (x, 0, 1))

Detail solution

Let $u = 8 x$ .

Then let $du = 8 dx$ and substitute $\frac{du}{8}$ :

$\int \frac{\sin{\left(u \right)}}{8}\, du$
1. The integral of a constant times a function is the constant times the integral of the function:
  
  $\int \sin{\left(u \right)}\, du = \frac{\int \sin{\left(u \right)}\, du}{8}$
  1. The integral of sine is negative cosine:
    
    $\int \sin{\left(u \right)}\, du = - \cos{\left(u \right)}$
  So, the result is: $- \frac{\cos{\left(u \right)}}{8}$
Now substitute $u$ back in:

$- \frac{\cos{\left(8 x \right)}}{8}$
Add the constant of integration:

$- \frac{\cos{\left(8 x \right)}}{8}+ \mathrm{constant}$

The answer is:

$- \frac{\cos{\left(8 x \right)}}{8}+ \mathrm{constant}$

The answer (Indefinite) [src]

  /                          
 |                   cos(8*x)
 | sin(8*x) dx = C - --------
 |                      8    
/

$$\int \sin{\left(8 x \right)}\, dx = C - \frac{\cos{\left(8 x \right)}}{8}$$

Simplify

The graph

Plot the graph f(x)

The answer [src]

1   cos(8)
- - ------
8     8

$$\frac{1}{8} - \frac{\cos{\left(8 \right)}}{8}$$

1   cos(8)
- - ------
8     8

$$\frac{1}{8} - \frac{\cos{\left(8 \right)}}{8}$$

1/8 - cos(8)/8

Numerical answer [src]

0.143187504226077

0.143187504226077

The graph

Use the examples entering the upper and lower limits of integration.