Mister Exam

Integral of sin(3x+2)dx dx

Limits of integration:

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The graph:

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Piecewise:

The solution

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01sin(3x+2)dx\int\limits_{0}^{1} \sin{\left(3 x + 2 \right)}\, dx
Integral(sin(3*x + 2), (x, 0, 1))
Detail solution
  1. Let u=3x+2u = 3 x + 2.

    Then let du=3dxdu = 3 dx and substitute du3\frac{du}{3}:

    sin(u)3du\int \frac{\sin{\left(u \right)}}{3}\, du

    1. The integral of a constant times a function is the constant times the integral of the function:

      sin(u)du=sin(u)du3\int \sin{\left(u \right)}\, du = \frac{\int \sin{\left(u \right)}\, du}{3}

      1. The integral of sine is negative cosine:

        sin(u)du=cos(u)\int \sin{\left(u \right)}\, du = - \cos{\left(u \right)}

      So, the result is: cos(u)3- \frac{\cos{\left(u \right)}}{3}

    Now substitute uu back in:

    cos(3x+2)3- \frac{\cos{\left(3 x + 2 \right)}}{3}

  2. Now simplify:

    cos(3x+2)3- \frac{\cos{\left(3 x + 2 \right)}}{3}

  3. Add the constant of integration:

    cos(3x+2)3+constant- \frac{\cos{\left(3 x + 2 \right)}}{3}+ \mathrm{constant}


The answer is:

cos(3x+2)3+constant- \frac{\cos{\left(3 x + 2 \right)}}{3}+ \mathrm{constant}

The answer (Indefinite) [src]
  /                                  
 |                       cos(3*x + 2)
 | sin(3*x + 2) dx = C - ------------
 |                            3      
/                                    
sin(3x+2)dx=Ccos(3x+2)3\int \sin{\left(3 x + 2 \right)}\, dx = C - \frac{\cos{\left(3 x + 2 \right)}}{3}
The graph
0.001.000.100.200.300.400.500.600.700.800.902-2
The answer [src]
  cos(5)   cos(2)
- ------ + ------
    3        3   
cos(2)3cos(5)3\frac{\cos{\left(2 \right)}}{3} - \frac{\cos{\left(5 \right)}}{3}
=
=
  cos(5)   cos(2)
- ------ + ------
    3        3   
cos(2)3cos(5)3\frac{\cos{\left(2 \right)}}{3} - \frac{\cos{\left(5 \right)}}{3}
-cos(5)/3 + cos(2)/3
Numerical answer [src]
-0.233269674003456
-0.233269674003456
The graph
Integral of sin(3x+2)dx dx

    Use the examples entering the upper and lower limits of integration.