The integral of a constant times a function is the constant times the integral of the function:
∫u24du=−∫u24du
The integral of un is n+1un+1 when n=−1:
∫u24du=25u25
So, the result is: −25u25
Now substitute u back in:
−25cos25(x)
The integral of a constant times a function is the constant times the integral of the function:
∫(−12sin(x)cos22(x))dx=−12∫sin(x)cos22(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u22)du
The integral of a constant times a function is the constant times the integral of the function:
∫u22du=−∫u22du
The integral of un is n+1un+1 when n=−1:
∫u22du=23u23
So, the result is: −23u23
Now substitute u back in:
−23cos23(x)
So, the result is: 2312cos23(x)
The integral of a constant times a function is the constant times the integral of the function:
∫66sin(x)cos20(x)dx=66∫sin(x)cos20(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u20)du
The integral of a constant times a function is the constant times the integral of the function:
∫u20du=−∫u20du
The integral of un is n+1un+1 when n=−1:
∫u20du=21u21
So, the result is: −21u21
Now substitute u back in:
−21cos21(x)
So, the result is: −722cos21(x)
The integral of a constant times a function is the constant times the integral of the function:
∫(−220sin(x)cos18(x))dx=−220∫sin(x)cos18(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u18)du
The integral of a constant times a function is the constant times the integral of the function:
∫u18du=−∫u18du
The integral of un is n+1un+1 when n=−1:
∫u18du=19u19
So, the result is: −19u19
Now substitute u back in:
−19cos19(x)
So, the result is: 19220cos19(x)
The integral of a constant times a function is the constant times the integral of the function:
∫495sin(x)cos16(x)dx=495∫sin(x)cos16(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u16)du
The integral of a constant times a function is the constant times the integral of the function:
∫u16du=−∫u16du
The integral of un is n+1un+1 when n=−1:
∫u16du=17u17
So, the result is: −17u17
Now substitute u back in:
−17cos17(x)
So, the result is: −17495cos17(x)
The integral of a constant times a function is the constant times the integral of the function:
∫(−792sin(x)cos14(x))dx=−792∫sin(x)cos14(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u14)du
The integral of a constant times a function is the constant times the integral of the function:
∫u14du=−∫u14du
The integral of un is n+1un+1 when n=−1:
∫u14du=15u15
So, the result is: −15u15
Now substitute u back in:
−15cos15(x)
So, the result is: 5264cos15(x)
The integral of a constant times a function is the constant times the integral of the function:
∫924sin(x)cos12(x)dx=924∫sin(x)cos12(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u12)du
The integral of a constant times a function is the constant times the integral of the function:
∫u12du=−∫u12du
The integral of un is n+1un+1 when n=−1:
∫u12du=13u13
So, the result is: −13u13
Now substitute u back in:
−13cos13(x)
So, the result is: −13924cos13(x)
The integral of a constant times a function is the constant times the integral of the function:
∫(−792sin(x)cos10(x))dx=−792∫sin(x)cos10(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u10)du
The integral of a constant times a function is the constant times the integral of the function:
∫u10du=−∫u10du
The integral of un is n+1un+1 when n=−1:
∫u10du=11u11
So, the result is: −11u11
Now substitute u back in:
−11cos11(x)
So, the result is: 72cos11(x)
The integral of a constant times a function is the constant times the integral of the function:
∫495sin(x)cos8(x)dx=495∫sin(x)cos8(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u8)du
The integral of a constant times a function is the constant times the integral of the function:
∫u8du=−∫u8du
The integral of un is n+1un+1 when n=−1:
∫u8du=9u9
So, the result is: −9u9
Now substitute u back in:
−9cos9(x)
So, the result is: −55cos9(x)
The integral of a constant times a function is the constant times the integral of the function:
∫(−220sin(x)cos6(x))dx=−220∫sin(x)cos6(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u6)du
The integral of a constant times a function is the constant times the integral of the function:
∫u6du=−∫u6du
The integral of un is n+1un+1 when n=−1:
∫u6du=7u7
So, the result is: −7u7
Now substitute u back in:
−7cos7(x)
So, the result is: 7220cos7(x)
The integral of a constant times a function is the constant times the integral of the function:
∫66sin(x)cos4(x)dx=66∫sin(x)cos4(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u4)du
The integral of a constant times a function is the constant times the integral of the function:
∫u4du=−∫u4du
The integral of un is n+1un+1 when n=−1:
∫u4du=5u5
So, the result is: −5u5
Now substitute u back in:
−5cos5(x)
So, the result is: −566cos5(x)
The integral of a constant times a function is the constant times the integral of the function:
∫(−12sin(x)cos2(x))dx=−12∫sin(x)cos2(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u2)du
The integral of a constant times a function is the constant times the integral of the function:
∫u2du=−∫u2du
The integral of un is n+1un+1 when n=−1:
∫u2du=3u3
So, the result is: −3u3
Now substitute u back in:
−3cos3(x)
So, the result is: 4cos3(x)
The integral of sine is negative cosine:
∫sin(x)dx=−cos(x)
The result is: −25cos25(x)+2312cos23(x)−722cos21(x)+19220cos19(x)−17495cos17(x)+5264cos15(x)−13924cos13(x)+72cos11(x)−55cos9(x)+7220cos7(x)−566cos5(x)+4cos3(x)−cos(x)
The integral of a constant times a function is the constant times the integral of the function:
∫u24du=−∫u24du
The integral of un is n+1un+1 when n=−1:
∫u24du=25u25
So, the result is: −25u25
Now substitute u back in:
−25cos25(x)
The integral of a constant times a function is the constant times the integral of the function:
∫(−12sin(x)cos22(x))dx=−12∫sin(x)cos22(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u22)du
The integral of a constant times a function is the constant times the integral of the function:
∫u22du=−∫u22du
The integral of un is n+1un+1 when n=−1:
∫u22du=23u23
So, the result is: −23u23
Now substitute u back in:
−23cos23(x)
So, the result is: 2312cos23(x)
The integral of a constant times a function is the constant times the integral of the function:
∫66sin(x)cos20(x)dx=66∫sin(x)cos20(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u20)du
The integral of a constant times a function is the constant times the integral of the function:
∫u20du=−∫u20du
The integral of un is n+1un+1 when n=−1:
∫u20du=21u21
So, the result is: −21u21
Now substitute u back in:
−21cos21(x)
So, the result is: −722cos21(x)
The integral of a constant times a function is the constant times the integral of the function:
∫(−220sin(x)cos18(x))dx=−220∫sin(x)cos18(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u18)du
The integral of a constant times a function is the constant times the integral of the function:
∫u18du=−∫u18du
The integral of un is n+1un+1 when n=−1:
∫u18du=19u19
So, the result is: −19u19
Now substitute u back in:
−19cos19(x)
So, the result is: 19220cos19(x)
The integral of a constant times a function is the constant times the integral of the function:
∫495sin(x)cos16(x)dx=495∫sin(x)cos16(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u16)du
The integral of a constant times a function is the constant times the integral of the function:
∫u16du=−∫u16du
The integral of un is n+1un+1 when n=−1:
∫u16du=17u17
So, the result is: −17u17
Now substitute u back in:
−17cos17(x)
So, the result is: −17495cos17(x)
The integral of a constant times a function is the constant times the integral of the function:
∫(−792sin(x)cos14(x))dx=−792∫sin(x)cos14(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u14)du
The integral of a constant times a function is the constant times the integral of the function:
∫u14du=−∫u14du
The integral of un is n+1un+1 when n=−1:
∫u14du=15u15
So, the result is: −15u15
Now substitute u back in:
−15cos15(x)
So, the result is: 5264cos15(x)
The integral of a constant times a function is the constant times the integral of the function:
∫924sin(x)cos12(x)dx=924∫sin(x)cos12(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u12)du
The integral of a constant times a function is the constant times the integral of the function:
∫u12du=−∫u12du
The integral of un is n+1un+1 when n=−1:
∫u12du=13u13
So, the result is: −13u13
Now substitute u back in:
−13cos13(x)
So, the result is: −13924cos13(x)
The integral of a constant times a function is the constant times the integral of the function:
∫(−792sin(x)cos10(x))dx=−792∫sin(x)cos10(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u10)du
The integral of a constant times a function is the constant times the integral of the function:
∫u10du=−∫u10du
The integral of un is n+1un+1 when n=−1:
∫u10du=11u11
So, the result is: −11u11
Now substitute u back in:
−11cos11(x)
So, the result is: 72cos11(x)
The integral of a constant times a function is the constant times the integral of the function:
∫495sin(x)cos8(x)dx=495∫sin(x)cos8(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u8)du
The integral of a constant times a function is the constant times the integral of the function:
∫u8du=−∫u8du
The integral of un is n+1un+1 when n=−1:
∫u8du=9u9
So, the result is: −9u9
Now substitute u back in:
−9cos9(x)
So, the result is: −55cos9(x)
The integral of a constant times a function is the constant times the integral of the function:
∫(−220sin(x)cos6(x))dx=−220∫sin(x)cos6(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u6)du
The integral of a constant times a function is the constant times the integral of the function:
∫u6du=−∫u6du
The integral of un is n+1un+1 when n=−1:
∫u6du=7u7
So, the result is: −7u7
Now substitute u back in:
−7cos7(x)
So, the result is: 7220cos7(x)
The integral of a constant times a function is the constant times the integral of the function:
∫66sin(x)cos4(x)dx=66∫sin(x)cos4(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u4)du
The integral of a constant times a function is the constant times the integral of the function:
∫u4du=−∫u4du
The integral of un is n+1un+1 when n=−1:
∫u4du=5u5
So, the result is: −5u5
Now substitute u back in:
−5cos5(x)
So, the result is: −566cos5(x)
The integral of a constant times a function is the constant times the integral of the function:
∫(−12sin(x)cos2(x))dx=−12∫sin(x)cos2(x)dx
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u2)du
The integral of a constant times a function is the constant times the integral of the function:
∫u2du=−∫u2du
The integral of un is n+1un+1 when n=−1:
∫u2du=3u3
So, the result is: −3u3
Now substitute u back in:
−3cos3(x)
So, the result is: 4cos3(x)
The integral of sine is negative cosine:
∫sin(x)dx=−cos(x)
The result is: −25cos25(x)+2312cos23(x)−722cos21(x)+19220cos19(x)−17495cos17(x)+5264cos15(x)−13924cos13(x)+72cos11(x)−55cos9(x)+7220cos7(x)−566cos5(x)+4cos3(x)−cos(x)