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- Improper integral
- Double Integral
- Triple Integral
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How to use it?
- Integral of d{x}:
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Integral of x^(-1/2)
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Integral of sin²xcos²x
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Integral of x*2^(-x)
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Integral of y^(-2/3)
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Identical expressions
- one /(x*lnx- one)
- 1 divide by (x multiply by lnx minus 1)
- one divide by (x multiply by lnx minus one)
- 1/(xlnx-1)
- 1/xlnx-1
- 1 divide by (x*lnx-1)
- 1/(x*lnx-1)dx
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Similar expressions
- 1/(xln(x-1))
- 1/(x(ln(x)-1))
- 1/(x(lnx-1)^4)
- 1/x*(lnx-1)^2
- 1/(x(lnx-1)^3)
- 1/(x*lnx+1)
Integral of 1/(x*lnx-1) dx
The solution
You have entered
[src]
oo / | | 1 | ------------ dx | x*log(x) - 1 | / 2 e
$$\int\limits_{e^{2}}^{\infty} \frac{1}{x \log{\left(x \right)} - 1}\, dx$$
Integral(1/(x*log(x) - 1), (x, exp(2), oo))
The answer (Indefinite)
[src]
/ / | | | 1 | 1 | ------------ dx = C + | ------------- dx | x*log(x) - 1 | -1 + x*log(x) | | / /
$$\int \frac{1}{x \log{\left(x \right)} - 1}\, dx = C + \int \frac{1}{x \log{\left(x \right)} - 1}\, dx$$
The answer
[src]
oo / | | 1 | ------------- dx | -1 + x*log(x) | / 2 e
$$\int\limits_{e^{2}}^{\infty} \frac{1}{x \log{\left(x \right)} - 1}\, dx$$
=
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oo / | | 1 | ------------- dx | -1 + x*log(x) | / 2 e
$$\int\limits_{e^{2}}^{\infty} \frac{1}{x \log{\left(x \right)} - 1}\, dx$$
Integral(1/(-1 + x*log(x)), (x, exp(2), oo))
Use the examples entering the upper and lower limits of integration.