Integral of 1/sqrt(y) dy
The solution
Detail solution
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Let u=y.
Then let du=2ydy and substitute 2du:
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The integral of a constant times a function is the constant times the integral of the function:
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The integral of a constant is the constant times the variable of integration:
∫1du=u
So, the result is: 2u
Now substitute u back in:
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Add the constant of integration:
2y+constant
The answer is:
2y+constant
The answer (Indefinite)
[src]
/
|
| 1 ___
| ----- dy = C + 2*\/ y
| ___
| \/ y
|
/
∫y1dy=C+2y
The graph
Use the examples entering the upper and lower limits of integration.