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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of sec^3
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Integral of sqrt(x)/x
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Integral of x^2*e^(-x)*dx
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Integral of (sinx-cosx)^2
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Identical expressions
- one /(sinx^ two - one)
- 1 divide by ( sinus of x squared minus 1)
- one divide by ( sinus of x to the power of two minus one)
- 1/(sinx2-1)
- 1/sinx2-1
- 1/(sinx²-1)
- 1/(sinx to the power of 2-1)
- 1/sinx^2-1
- 1 divide by (sinx^2-1)
- 1/(sinx^2-1)dx
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Similar expressions
- 1/(sinx^2+1)
Integral of 1/(sinx^2-1) dx
The solution
You have entered
[src]
1 / | | 1 | 1*----------- dx | 2 | sin (x) - 1 | / 0
$$\int\limits_{0}^{1} 1 \cdot \frac{1}{\sin^{2}{\left(x \right)} - 1}\, dx$$
Integral(1/(sin(x)^2 - 1*1), (x, 0, 1))
The answer (Indefinite)
[src]
/ /x\ | 2*tan|-| | 1 \2/ | 1*----------- dx = C + ------------ | 2 2/x\ | sin (x) - 1 -1 + tan |-| | \2/ /
$$\int 1 \cdot \frac{1}{\sin^{2}{\left(x \right)} - 1}\, dx = C + \frac{2 \tan{\left(\frac{x}{2} \right)}}{\tan^{2}{\left(\frac{x}{2} \right)} - 1}$$
The graph
The answer
[src]
2*tan(1/2)
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2
-1 + tan (1/2)
$$\frac{2 \tan{\left(\frac{1}{2} \right)}}{-1 + \tan^{2}{\left(\frac{1}{2} \right)}}$$
=
=
2*tan(1/2)
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2
-1 + tan (1/2)
$$\frac{2 \tan{\left(\frac{1}{2} \right)}}{-1 + \tan^{2}{\left(\frac{1}{2} \right)}}$$
The graph
Use the examples entering the upper and lower limits of integration.