Integral of 1/(sinx^2-1) dx
The solution
The answer (Indefinite)
[src]
/ /x\
| 2*tan|-|
| 1 \2/
| 1*----------- dx = C + ------------
| 2 2/x\
| sin (x) - 1 -1 + tan |-|
| \2/
/
∫1⋅sin2(x)−11dx=C+tan2(2x)−12tan(2x)
The graph
2*tan(1/2)
--------------
2
-1 + tan (1/2)
−1+tan2(21)2tan(21)
=
2*tan(1/2)
--------------
2
-1 + tan (1/2)
−1+tan2(21)2tan(21)
Use the examples entering the upper and lower limits of integration.