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How to use it?
- Integral of d{x}:
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Integral of (1-x^2)/(1+x^2)
- Integral of x^2*a^x
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Integral of x^2/(x^2-4)
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Integral of sen
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Identical expressions
- one /(sinx+cosx)^2dx
- 1 divide by ( sinus of x plus co sinus of e of x) squared dx
- one divide by ( sinus of x plus co sinus of e of x) squared dx
- 1/(sinx+cosx)2dx
- 1/sinx+cosx2dx
- 1/(sinx+cosx)²dx
- 1/(sinx+cosx) to the power of 2dx
- 1/sinx+cosx^2dx
- 1 divide by (sinx+cosx)^2dx
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Similar expressions
- 1/(sinx-cosx)^2dx
Integral of 1/(sinx+cosx)^2dx dx
The solution
You have entered
[src]
1 / | | 1 | ------------------ dx | 2 | (sin(x) + cos(x)) | / 0
$$\int\limits_{0}^{1} \frac{1}{\left(\sin{\left(x \right)} + \cos{\left(x \right)}\right)^{2}}\, dx$$
Integral(1/((sin(x) + cos(x))^2), (x, 0, 1))
The answer (Indefinite)
[src]
/ /x\ | 2*tan|-| | 1 \2/ | ------------------ dx = C - ----------------------- | 2 2/x\ /x\ | (sin(x) + cos(x)) -1 + tan |-| - 2*tan|-| | \2/ \2/ /
$$\int \frac{1}{\left(\sin{\left(x \right)} + \cos{\left(x \right)}\right)^{2}}\, dx = C - \frac{2 \tan{\left(\frac{x}{2} \right)}}{\tan^{2}{\left(\frac{x}{2} \right)} - 2 \tan{\left(\frac{x}{2} \right)} - 1}$$
The graph
The answer
[src]
-2*tan(1/2)
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2
-1 + tan (1/2) - 2*tan(1/2)
$$- \frac{2 \tan{\left(\frac{1}{2} \right)}}{- 2 \tan{\left(\frac{1}{2} \right)} - 1 + \tan^{2}{\left(\frac{1}{2} \right)}}$$
=
=
-2*tan(1/2)
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2
-1 + tan (1/2) - 2*tan(1/2)
$$- \frac{2 \tan{\left(\frac{1}{2} \right)}}{- 2 \tan{\left(\frac{1}{2} \right)} - 1 + \tan^{2}{\left(\frac{1}{2} \right)}}$$
-2*tan(1/2)/(-1 + tan(1/2)^2 - 2*tan(1/2))
Use the examples entering the upper and lower limits of integration.