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Integral of 1/(2sinx+sin2x) dx

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The solution

You have entered [src]
  1                         
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 |             1            
 |  1*------------------- dx
 |    2*sin(x) + sin(2*x)   
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01112sin(x)+sin(2x)dx\int\limits_{0}^{1} 1 \cdot \frac{1}{2 \sin{\left(x \right)} + \sin{\left(2 x \right)}}\, dx
Integral(1/(2*sin(x) + sin(2*x)), (x, 0, 1))
The answer (Indefinite) [src]
(sin2(2x)+4sinxsin(2x)+cos2(2x)+(4cosx+2)cos(2x)+4sin2x+4cos2x+4cosx+1)log(sin2x+cos2x+2cosx+1)+(sin2(2x)4sinxsin(2x)cos2(2x)+(4cosx2)cos(2x)4sin2x4cos2x4cosx1)log(sin2x+cos2x2cosx+1)4sinxsin(2x)4cosxcos(2x)8sin2x8cos2x4cosx8sin2(2x)+32sinxsin(2x)+8cos2(2x)+(32cosx+16)cos(2x)+32sin2x+32cos2x+32cosx+8-{{\left(\sin ^2\left(2\,x\right)+4\,\sin x\,\sin \left(2\,x\right) +\cos ^2\left(2\,x\right)+\left(4\,\cos x+2\right)\,\cos \left(2\,x \right)+4\,\sin ^2x+4\,\cos ^2x+4\,\cos x+1\right)\,\log \left(\sin ^2x+\cos ^2x+2\,\cos x+1\right)+\left(-\sin ^2\left(2\,x\right)-4\, \sin x\,\sin \left(2\,x\right)-\cos ^2\left(2\,x\right)+\left(-4\, \cos x-2\right)\,\cos \left(2\,x\right)-4\,\sin ^2x-4\,\cos ^2x-4\, \cos x-1\right)\,\log \left(\sin ^2x+\cos ^2x-2\,\cos x+1\right)-4\, \sin x\,\sin \left(2\,x\right)-4\,\cos x\,\cos \left(2\,x\right)-8\, \sin ^2x-8\,\cos ^2x-4\,\cos x}\over{8\,\sin ^2\left(2\,x\right)+32 \,\sin x\,\sin \left(2\,x\right)+8\,\cos ^2\left(2\,x\right)+\left( 32\,\cos x+16\right)\,\cos \left(2\,x\right)+32\,\sin ^2x+32\,\cos ^ 2x+32\,\cos x+8}}
The answer [src]
  1                       
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 |           1            
 |  ------------------- dx
 |  2*sin(x) + sin(2*x)   
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  1                       
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 |           1            
 |  ------------------- dx
 |  2*sin(x) + sin(2*x)   
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0                         
0112sin(x)+sin(2x)dx\int\limits_{0}^{1} \frac{1}{2 \sin{\left(x \right)} + \sin{\left(2 x \right)}}\, dx
Numerical answer [src]
11.082058518454
11.082058518454

    Use the examples entering the upper and lower limits of integration.